can u explain aadi to me oct 2003 p 4 q 5
Q5.
(a)
i) Two cards have D, out of 10, so 2/10 = 0.2
ii)4 cards are red, out of the 10, so 4/10 = 0.4
iii)Remember Probability of A
OR B= P(A) + P(B) - P(A intersection B)
Here, Prob. of being red: 4/10. Prob. of being D: 2/10. Prob. of being Red
AND (intersection) D at the same time, is 1/10 (as only ONE card Is both red AND has D)
So prob of red + prob of D - prob of Red and D = 4/10 + 2/10 - 1/10 = 5/10 = 0.5
iv) Prob of red: 4/10 prob the card is D OUT of the red: 1/4
So, prob red X prob of D OUT OF Red = 4/10 X 1/4 = 4/40 = 0.1
v) There is NO CARD THAT IS RED with AN N ON IT. So, ZERO. 0.
