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Author Topic: IGCSE MATHS Doubts  (Read 130620 times)

Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #330 on: May 11, 2010, 10:08:26 am »
Quote from: princess12 on May 11, 2010, 10:04:43 am
oct/nov 2008 p2 q6
 ??? ??? ???

sin-1 (0.86603)

should get 60 .. or 120 :)
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Offline Ghost Of Highbury

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Re: IGCSE MATHS Doubts
« Reply #331 on: May 11, 2010, 10:08:52 am »
Quote from: ~VIN1094~ on May 11, 2010, 10:08:26 am
sin-1 (0.86603)

should get 60 .. :)

and 120.

The All Silver Tea Cups rule :P
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Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #332 on: May 11, 2010, 10:11:26 am »
Quote from: A@di on May 11, 2010, 10:08:52 am
and 120.

The All Silver Tea Cups rule :P

ya i was in a hurry .. n also didnt see u'd alredy posted .. i hate it wen tht message appears ..n i dont even bother to look down .. :P
By the way wer were u yest ?? tons on ques ware booming at the physics thread .. :)
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Offline Ghost Of Highbury

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Re: IGCSE MATHS Doubts
« Reply #333 on: May 11, 2010, 10:12:48 am »
sorry man, i was really busy yesterday, i saw those questions, but didnt have time to open the papers and answer them. thanks a lot for answering them all. gr8 work . +rep.

i was watching the premier league highlights..with my friends.. :)
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Offline Adzel

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Re: IGCSE MATHS Doubts
« Reply #334 on: May 11, 2010, 10:18:05 am »
Quote from: A@di on May 11, 2010, 09:40:08 am

14b) assume y= -2

   do the calculations, arrange them in order
 

I got: y3 < y2 < y0 < y-1

but mark scheme says: y3 < y-1 < y0 < y2
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Offline Adzel

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Re: IGCSE MATHS Doubts
« Reply #335 on: May 11, 2010, 10:32:35 am »
Answer this one please too; +explaination
« Last Edit: May 11, 2010, 10:34:40 am by Adzel »
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Offline thenewkid™

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Re: IGCSE MATHS Doubts
« Reply #336 on: May 11, 2010, 10:33:18 am »
may/june 2009 q18 variant 1 pls
Thanks
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Offline Ghost Of Highbury

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Re: IGCSE MATHS Doubts
« Reply #337 on: May 11, 2010, 10:39:08 am »
Quote from: Adzel on May 11, 2010, 10:18:05 am
I got: y3 < y2 < y0 < y-1

but mark scheme says: y3 < y-1 < y0 < y2

ur way : -8 < 4 < 1 < -0.5 = incorrect

ms way : -8 < -0.5 < 1 < 4 = correct

check ur calculations again :)

(-2)^3 = -8

(-2)^2 = 4
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Offline Baladya

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Re: IGCSE MATHS Doubts
« Reply #338 on: May 11, 2010, 10:44:36 am »
If we want to calculate lower and upper bound of lets say 6-4.
For upper bound we minus 6.5 minus 3.5 and for lower bound 5.5 - 4.5?

Thanks
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Offline Adzel

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Re: IGCSE MATHS Doubts
« Reply #339 on: May 11, 2010, 10:45:03 am »
Ans Q18 (a)   1080           33
                  ------- =  -------- = 320 cm3
                      s             23

          
            (b)      s             32
                  ------- =  --------  = 567 cm2
                    252            22
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Offline Adzel

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Re: IGCSE MATHS Doubts
« Reply #340 on: May 11, 2010, 10:47:24 am »
Quote from: A@di on May 11, 2010, 10:39:08 am
ur way : -8 < 4 < 1 < -0.5 = incorrect

ms way : -8 < -0.5 < 1 < 4 = correct

check ur calculations again :)

(-2)^3 = -8

(-2)^2 = 4


oops I forgot to put the brackets...thanks
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Offline Ghost Of Highbury

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Re: IGCSE MATHS Doubts
« Reply #341 on: May 11, 2010, 10:48:29 am »
Quote from: Adzel on May 11, 2010, 10:32:35 am
Answer this one please too; +explaination

attached.

PQS = 80 degree.

Angle PQS = Angle PRS

the chord circumference rule.

QPR = 180 - 80 - 33 = 67 degree. (Angle Sum property)

PSQ => PXS = 147 (180-33). PSX = 180 - 147 - 21 = 12 degree. 
« Last Edit: May 11, 2010, 10:53:18 am by A@di »
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Offline Adzel

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Re: IGCSE MATHS Doubts
« Reply #342 on: May 11, 2010, 10:49:46 am »
Quote from: Baladya on May 11, 2010, 10:44:36 am
If we want to calculate lower and upper bound of lets say 6-4.
For upper bound we minus 6.5 minus 3.5 and for lower bound 5.5 - 4.5?

Thanks

...to the nearest what?
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Offline astarmathsandphysics

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Re: IGCSE MATHS Doubts
« Reply #343 on: May 11, 2010, 10:51:18 am »
WHOLE NUMBER
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Offline Baladya

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Re: IGCSE MATHS Doubts
« Reply #344 on: May 11, 2010, 10:53:27 am »
Quote from: Adzel on May 11, 2010, 10:49:46 am
...to the nearest what?

Ya whole number... My question is that we should do it like dividing (upper bound of 1st number - lower bound of 2nd number)
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