Qualification > Math
IGCSE MATHS Doubts
saleemsamer:
--- Quote from: saleemsamer on May 18, 2010, 05:05:46 pm ---can some1 plz explain jun 2007 p4 q 2f and 4 c-e :)
--- End quote ---
mdwael:
--- Quote from: mdwael on May 18, 2010, 05:19:33 pm ---They may sound a stupid question but to me its not. Its this question in summer 2000 paper 4 page 7 c(i) part it says "explain why the point (60,280) is on the curve?" this is the first time I face this kind of question, I was hoping someone could explain it to me
By the way the MS says its "end of interval is 60, 20+40+200" ??? ???
--- End quote ---
Please answer my question, before I start headbutting the walls >:( :P
thenewkid™:
--- Quote ---Question2.C may/june 2006 paper4
How to solve this question
i have been tryiing to solve it from the past 20 mints
--- End quote ---
for part c multiply the area of the cross-section by 40
as for the surface area calculate the area of each of its faces and add them together
Vin:
--- Quote from: Shooting Star on May 18, 2010, 05:20:26 pm ---um.. i still dont get it... can u elaborate a bit more. By the way the ans in the ms is 2 days 13 hours
--- End quote ---
sorry im on a real hurry doin french maths together !! im sorry if u see again the working is right .. so wat didnt u understand ??
When the pool is emptied, the water flows through a cylindrical pipe of radius 12.5 cm.
so the volume of pool is emptied i.e
volume of pool = 1512 m3 * 100 *100 *100
=1512000000 cm3
The water flows along this pipe at a rate of 14 centimetres per second.
so the area of pipe is pi * 12.52 =490.874 cm2
flows at 14cm/s so volume per second = 490.874 cm2 * 14cm/s
= 6870 cm3
Calculate the time taken to empty the pool.
Give your answer in days and hours, correct to the nearest hour.
volume emptying
---------------
rate of vol emptying
=1512000000 cm3
-----------------
6870 cm3/sec
=ans / 60(min) * 60(hrs) *24
=2.5473 days
=2 days 13 hrs
Ghost Of Highbury:
--- Quote from: Nidzzz on May 18, 2010, 05:29:08 pm ---hey same doubt here de last part is cofusin can any1 help wid this
thanku
--- End quote ---
look at diagram 2
the shape ABO has an area of = 90/360 * 144pi = 113
area of the horizontal rectangle = (12+10=22) * (18-12=6) = 132
area of the BOCG = 12*10 = 120
total = 365
365*40 = 14600cm^3
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version