Qualification > Math
IGCSE MATHS Doubts
Saladin:
--- Quote from: A@di on May 18, 2010, 10:12:19 am ---yes, provided u have do the other paper well..
--- End quote ---
Which question are you up to?
Ghost Of Highbury:
--- Quote from: LM on May 18, 2010, 06:36:15 am ---I have so many questions to ask all of you..
and all of them comes from Nov 07/paper 4
http://www.freeexampapers.us/IGCSE/Maths/CIE/2007%20Nov/0580_w07_qp_4.pdf
here are the question :
Q2 (a)(vi)
Q3 (b) (c) (f)
Q4 (b) (c)
Q5 (b) (c)(v)
Q6 (b)(ii)(iii)
Q7 (d)(ii) (e)
Q8 (b)(c)(d)(e)
Q9 (b)(v)(vi) (d)
Please answer it ASAP!
Tomorrow is the exam!!
--- End quote ---
@Engraved/Dude - Start solving these...ill join u soon, solving the previous ones posted by "big mac"
LM:
--- Quote from: A@di on May 18, 2010, 11:06:06 am ---@Engraved/Dude - Start solving these...ill join u soon, solving the previous ones posted by "big mac"
--- End quote ---
I did do the whole paper...
those are the only questions left...
you see I need all the help....
Vin:
--- Quote from: LM on May 18, 2010, 11:09:35 am ---I did do the whole paper...
those are the only questions left...
you see I need all the help....
--- End quote ---
i'd typed out till ques 6 !!.. im using my laptop n it shut down unexpectedly !!! =@ aargh !! all waste im sorry i might not be able to help i need to study =\
Ghost Of Highbury:
--- Quote from: LM on May 18, 2010, 11:09:35 am ---I did do the whole paper...
those are the only questions left...
you see I need all the help....
--- End quote ---
2avi) this means that the order shud be like this : Not from 5th grade, not from 5th grade, from 5th grade
Students not from 5th grade = 24. Total = 28
first student not from 5th grade = 24/28
second student not from 5th grade = 23/27 (23 because 1 student has already been picked, 28-1 = 27)
third student is a fifth grader = 4/26 (26 because 2 students hav already been picked)
(24/28)^2 * 4/26 = 92/819
3b) arrange it in the form of y = mx + x where 'm' is the gradient and 'c' is the y-intercept.
y = 4-x ----> y = -x + 4 ---> y = -1(x) + 4
thus m = -1.
3c) this means find the x-values for which the point on the curve has a negative gradient. in this, a parabola, all points in the part of the curve in the second quadrant has a negative gradient. Thus, when x<0, gradient = negative.
3f) apply x = +/-
u shud get 1.3 and -2.3
The answers i.e 1.3 and -2.3 are the x-cordinates of the point B and A respectively.
y = 4-x
y = 4-1.3 = 2.7
y = 4-x
y = 4+2.3 = 6.3
A - (-2.3, 6.3) B - (1.3, 2.7)
(x1+x2)/2 = (-2.3+1.3)/2 = -0.5
(y1+y2)/2 = (6.3+2.7)/2 = 4.5
midpoint = (-0.5,4.5)
4b) Volume of water in the first diagram = pi*8^2*8 = 1608.5
Total volume of the two spheres = 180*2 = 360cm^3
Total volume of spheres and water = 1968.5
pi*8^2*h = 1968.5
h = 1968.5/64pi = 9.79
4c) 4.8g = 1cm^3
1000g = 1000/4.8 = 208.33cm^3
4/3pi*r^3 = 208.33
r = cube root of 49.73 = 3.67
5b) 2*0.5*8×’5.74’+2*0.5*6×’6.32’ +8×6 = 131.84
5c) the triangle PHN divides the pyramid into 2. thus, ans = PHN
6bii) Angle BDC = 100-58.6 = 41.4
(BC)^2 = 182 + 302 - 2*18*30*cos 41.4 = 1224 - 810.11 = 414
BC = = 20.3m
biii) area of triangle ADB + BDC = 0.5 * 26 *30sin'41.4' + 0.5 *18* 30sin'41.4' = 436
7dii) so the new co-ordinates are
(8,6) --> (4,3)
(10,12)--> (5,6)
(6,10) --> (3,5)
plot them.
if u observe carefully, ull see dii) it is an enlargement of factor 0.5 and the center (0,0)
e) check the diagram
8b) 3/(2x-1) + 1
(2+2x)(2x-1)
c) y = 3/x +1
x=3/y + 1
x-1 = 3/y
xy -y = 3
y(x-1) = 3
y = 3/(x-1)
g-1(x) = 3/(x-1)
d) h(3) = 8
h(8) = 2^8 = 256
e) g(-24/7) = 0.125
h(x) = 0.125
2^x = 0.125
2^x = 2^(-3)
x = -3
9bv) 3^(n-1)
bvi) Sequence S - Sequence T = (n+1)^2 - 3^(n-1)
d) 3^(n-1) = 177147= 3^11
n-1 = 11
n= 12
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