Qualification > Math

IGCSE MATHS Doubts

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-Cornea:
inverse the normal things u do:D tht's it

$H00t!N& $t@r:

--- Quote from: Fastal on May 10, 2010, 08:24:26 am ---i dont understand this part, i get everything else

--- End quote ---

Look, in the question before this (7a) the question was f(0.5) so u replace the x in f(x)=10^x with o.5 and you get 3.16

However, this is not the case in the second one. Here you're meant to find the inverse f^-1 (1)
so it will be the other way round. The 1 in the bracket (f^-1 (1)) will be replaced with f(x)  in f(x)=10^x
giving you 1= 10^x

If you still dont understand can you please specify what is it that you dont understand

-Cornea:
may june 2008 construction and locus question plzzz :)

Fastal:

--- Quote from: Shooting Star on May 10, 2010, 09:12:04 am ---Look, in the question before this (7a) the question was f(0.5) so u replace the x in f(x)=10^x with o.5 and you get 3.16

However, this is not the case in the second one. Here you're meant to find the inverse f^-1 (1)
so it will be the other way round. The 1 in the bracket (f^-1 (1)) will be replaced with f(x)  in f(x)=10^x
giving you 1= 10^x

If you still dont understand can you please specify what is it that you dont understand

--- End quote ---

hmm, we have a different way of finding inverse in school
suppose f(x)=2x+1
than f-1(x) is replace by y

y=2x+1(y and x are then switched)

x=2y+1
thus y=(x-1)/2
and f-1(x)=(x-1)/2

so can you tell me how to do it this way what is F-1(x) when f(x)=10x

-Cornea:
that's right inverse it in this way: ;D
but if it's like this question instead of removing x remove y
listen f(x)---> remove x
        f^-1--->opposite remove (y)
Got it:D

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