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IGCSE MATHS Doubts

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Vin:
f-1(x) =       x + 1
                   3
                         
put 3x - 1 as x in eqn 1 ..u'll get it

(3x -1) - 1
-----------
     3


= x

SEL123:
I get really confused when we're asked questions on shear and stretch..

I asked my tutor and he said for IGs the invariant like is ALWAYS either the x-axis or the y-axis...

To someone who has practiced past papers

Is that true??

Fastal:

--- Quote from: Pink Princess on May 09, 2010, 10:10:30 pm ---listen when u do f(x) u remove the X and replace it by the number given
now it's f^-1(x) so replace the y by 1 instead of replacing x because it's inverse
so it will be:
1=10^x
Anything to the power of zero =1
so x =0

listen u just need to find the perimeter of the shape
4*4 i.e(4+4+4+4) +2*pie*1.2 i.e(4*0.25*2*pie*1.2)
i guess the answer will be 23.5 approximatly it's 24 ppl (or if u want to add this half person :P)

--- End quote ---

i dont understand the function part.



and i still dont get how its vertically left for that shear question in 09November paper 4

$H00t!N& $t@r:

--- Quote from: Fastal on May 10, 2010, 05:52:03 am ---i dont understand the function part.

--- End quote ---

The function given to you is:   f(x)= 10^x
The question says: write down the value of f^-1(1)
Take the 1 in the bracket from f^-1(1) and put it on the other side
So now it becomes 1= 10^x
One of the law in indices is the zero index law which says that any number raised to the power of 0 is equal to 1
After rearranging we have 1 as the answer so that means that 10 is raised to 0
Therefore x=0
Hope that helps!  :)

Fastal:

--- Quote from: Shooting Star on May 10, 2010, 08:20:24 am ---Take the 1 in the bracket from f^-1(1) and put it on the other side
So now it becomes 1= 10^x

--- End quote ---

i dont understand this part, i get everything else

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