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IGCSE MATHS Doubts

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ksitna:
june 07 p2

Fastal:
the question is actually an expression

(x-3/4) + (4/x-3)

so here its
x2 + 9 - 6x + 16/4x-12

so you get +25

@d!_†oX!©:
I know you got this already, but i don't mind elaborating :P  

        90  
     S  |  A
180----------0/360
     T  |  C  
       270
Read the above as follows before starting:
1) A=All +ve , S= Sin +ve , T=Tan +ve , C=Cos +ve
2) This shows the four quadrants, going anticlockwise from 0 to 90 to 180 270 to 360.
3) This means that any angle in a specific quadrant is +ve acc to 1)
So, now coming to your question, the question is talking about sin, which is +ve in the 1st and 2nd quadrant.
The angle already given to us is in the 1st quadrant, so now we know we will get the same value in the second quadrant in the 2nd quadrant (180-x) or the after 360 (360+x)
Taking -50 to be x
we have the other two angles as,
180-(-50) = 180+50 = 230
360+(-50) = 360-50 = 310
:D hope that helps, not specifically for this question, but in general.

idrees:
hey i really need help with this Q.

its killing me! if someone could just explain the dynamics of this q .. how do i go about solving the question. thats all i need .. im really good at mensuration, i have just forgotten how to solve questions regarding rate of flow of water ..

June 2007 p4 Q7

Thanks a LOT!

Fastal:

--- Quote from: idrees on May 08, 2010, 06:48:34 pm ---hey i really need help with this Q.

its killing me! if someone could just explain the dynamics of this q .. how do i go about solving the question. thats all i need .. im really good at mensuration, i have just forgotten how to solve questions regarding rate of flow of water ..

June 2007 p4 Q7

Thanks a LOT!

--- End quote ---

the question means that 0.3*1.2*3 m3 flows in 1 minute so 1 hour is 64.8 m3

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