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IGCSE MATHS Doubts

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haris94:
anytime  ;)

bulono:
another doubt M/J 2005 Q 2 c......

bulono:
and in M/J 2005 Q 3 b how do i find the matrix....

Shazizzzle:
Sin x = Perp. / Hyp. (Some People Have)
Cos x = Base/Hyp. (Curly Brown Hair)
Tan x = Perp./Base (Through Proper Brushing)

Some people have, curly brown hair, through proper brushing. :P

And the perpendicular (opposite) of ANY angle, is the side opposite of the angle.
That automatically makes the other side which is NOT the hyp. the base.
So, The Base and Perpendicular may be different for different angles in a right angled triangle

Then, Sine Rule.

Sin A     Sin B       Sin C
-----  = ------  = -------
  A           B            C

Then, Cosine rule.

a^2 = b^2 + c^2 - 2bc X Cos A
b^2 = a^2 + c^2 - 2ac X Cos B
c^2 = a^2 + b^2 - 2ab X Cos C

OR, if angle is needed,

Cos A = b^2 + c^2 - a^2 / 2bc (Note, the angle to be found is A. So on top, the last one being -sed will be a^2 - And the two being added above, will be the ones multiplying with 2 below)

Vin:

--- Quote from: bulono on May 18, 2010, 09:30:13 pm ---help needed M/J 2004 question 2 c.....mine is 11 00 am GMT 3+

--- End quote ---

f(x) = x2 - x - 3

g(x) = 6 - X3/3

x2 - x - 3 = 6 - x3/3

x2 - x - 3  = 18 - x3
                            ---------
                                3
3x2 - 3x - 9 =  18 - x3

x3 + 3x2 - 3x - 9 - 18 = 0

x3 + 3x2 - 3x - 27 = 0

ii) find the intersection of these two graphs and write down the coordinates

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