JAN 2009 8 b (ii) :
As i said before:
y-intersections-----> put x=0:
(1)^2 (2-0)= 2 --------> (0,2)
x-intersections-----> put y=0:
x=-1, 2 --------) (-1,0) (-1,0) (2,0)
Then draw a cubic graph...since coefficient of x^3 <0 (when u expand the function), it will take the negative parabola form..
THATS IT! lol