Qualification > Math

C1 edexcel doubts!!!

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Amr Fouad:
JAN 2007 3:

(a) All u've gotta do is to transform the y-coordinates 3 upwards....

Therefore, the x- asymptote doesnt change..

but the y-asymptote changes to +3 (0+3=3)

In other words, The whole graph shifts by +3 units upwards..x-coordinates dont change


(b) It crosses the x-axis when y=0:

(1/x)+3=0

(1/x)= -3

x= -1/3


It crosses the y-axis when x=0:

(1/0)+3 =y

It gives us math error, therefore it doesnt corss the y-axis

Therefore, only coordinates:

(-1/3, 0)

Amr Fouad:

--- Quote from: Igcseboy on April 22, 2010, 12:47:03 pm ---in may 2005 11 d how is RS the ht..

Ya i have prb. with area of triangles in C1 :D

--- End quote ---

RS is the height as it already told you its perpendicular to the base....got it?

Igcseboy:

--- Quote from: ~ A.F ~ on April 22, 2010, 12:51:19 pm ---RS is the height as it already told you its perpendicular to the base....got it?

--- End quote ---


oh yes!!!! so the ht.. will always be the one perpendicular to the base?????

Amr Fouad:
MAY 2007 5:

(a) We have to transofrmations..

1. Multiplying the whole function by 3-----> i.e. multiply the y-coordinates by 3-----> still no change in general shape of the curve..

2. +3 near x-----> i.e subtract 3 from x-coordinates ------> graph moves by 3 units to the left...

Asypmtotes:

y-asymptoe: 3x 0=0

x-asymptote: 0-3=-3

Finding coordinates:

Only with y-axis: put x=0:

therefore------> (0, 3/2)

Igcseboy:

--- Quote from: ~ A.F ~ on April 22, 2010, 12:39:45 pm ---MAY 2005 Question 8 c:

Area= 0.5 x base x height

base= OC = 7

Height= x-coordinate of P as its perpendicular to the base = 3

Therefore Area- 0.5 x base x height

--- End quote ---


here it is not mentioned tht P is perpendicular???

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