Qualification > Math

C1 Edexcel Jan2010 Question! Please help!

<< < (4/9) > >>

~ A.F ~:
whats the "?" in ur question?

halosh92:
Giving your answers in terms of pie, solve the equation
3 tan2 thita - 1=0
for thita in the interval ?pie ? thita ? pie

halosh92:
(a) Given that t = log3 x, find expressions in terms of t for
(i) log3 x2,
(ii) log9 x.
(b) Hence, or otherwise, find to 3 significant figures the value of x such that
log3
x2 ? log9 x = 4.

how to do part aii

nid404:

--- Quote from: halosh92 on April 26, 2010, 12:57:54 pm ---Giving your answers in terms of pie, solve the equation
3 tan2 thita - 1=0
for thita in the interval -pie < thita < pie

--- End quote ---

tan 2 theta= 1/3
2 theta= tan inverse of 1/3
2 theta= 18.4
theta=9.22
period of tan 2theta= +-90 [2theta right...so it will be half the tan theta period...1/2 of 180]
       = 9.22, 99.22, -80.78, -170.78

T.Q:

--- Quote from: halosh92 on April 26, 2010, 12:58:59 pm ---(a) Given that t = log3 x, find expressions in terms of t for
(i) log3 x2,
(ii) log9 x.
(b) Hence, or otherwise, find to 3 significant figures the value of x such that
log3
x2 ? log9 x = 4.

how to do part aii

--- End quote ---

for part aii

change the base

and make it 3

so it will be like this   (log3 x) /(log3 9)

so log3 x = t

and log3 9 = 2

so the answer is (1/2 t)

Navigation

[0] Message Index

[#] Next page

[*] Previous page