Qualification > Math

M1 doubt .. URGENT..

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Amr Fouad:
it gets really simple now..

first, you have got to find the tension:
T=3gsin30+3a
or
T=2gsin60-2a

then there's a genral rule to find normal force on pulley:

R=T x square root{2(1+cos theta)}

where theta equals the angle between the two ropes, int his case 90 degrees..

Try it..

vanibharutham:
You have to consider it as pythagoras :P

or just learn this formula:

THE REACTION ON A PULLEY BY STRING = 2 x TENSION cos ( 90 - theta / 2 ), where theta is angle of slope

Amr Fouad:

--- Quote from: vanibharutham on April 17, 2010, 09:36:49 am ---You have to consider it as pythagoras :P

or just learn this formula:

THE REACTION ON A PULLEY BY STRING = 2 x TENSION cos ( 90 - theta / 2 ), where theta is angle of slope



--- End quote ---

mine is easier :P..and works all the time :P

crazed2009:
Thanks a LOT guys... :D its weird we never took these formulas, nt tht i remeber at least..
but wht about the rest of the question.. the angle btn the force and the vertical???

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