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Author Topic: STATASTICS DOUT  (Read 698 times)

Offline joel

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STATASTICS DOUT
« on: April 16, 2010, 09:57:08 am »
The probability of an event A occurs is P(A) = 0.3 The event B is independent of A and P(B) = 0.4.

Calculate P(A or B or both occur).

The answer is 0.58.

I would like to to know how to arrive at this answer.

The question is from Cambridge Advanced Level Mathematics Statistics 1 by Steve Dobbs and Jane Miller, Miscellaneous Exercise 4, Question 2 part (a).

Can someone please explain how to arrive at the answer.   
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Offline T.Q

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Re: STATASTICS DOUT
« Reply #1 on: April 16, 2010, 10:12:30 am »
dont double post

just post in the right place once , and we will see it
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holtadit

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Re: STATASTICS DOUT
« Reply #2 on: April 16, 2010, 10:16:51 am »
I get 0.82

Are you sure 0.58 is the right answer ? Just check again.
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Offline joel

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Re: STATASTICS DOUT
« Reply #3 on: April 16, 2010, 02:15:38 pm »
Yes I sure...
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Offline astarmathsandphysics

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Re: STATASTICS DOUT
« Reply #4 on: April 16, 2010, 05:25:45 pm »
P(aub)=p(a)+p(b)-p(anb) with p(anb)=p(a)*p(b) cos a and b are independent.
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