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physics!!

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nid404:
This is crazy....I've tried everything to come to the answer!! >:( >:(

Please help

check the attachment for the diagram

At the moment of release, the shot is 2.3m above the ground. The shot has a mass of 7.3kg. Calculate the kinetic energy of the shot at the moment of release....
How on earth is the ans 1713J  am I using the wrong velocity...we're supposed to use the resultant right? in the direction of 12m/s ???

nid404:
Help? ::) Pleeaasseeeee :-*

nid404:
http://books.google.co.in/books?id=4GUxeWap9qcC&pg=PA110&lpg=PA110&dq=At+the+moment+of+release,+the+shot+is+2.3m+above+the+ground.+The+shot+has+a+mass+of+7.3kg.+Calculate+the+kinetic+energy+of+the+shot+at+the+moment+of+release&source=bl&ots=BiPH-ngkim&sig=4FJ2IoVev9CwHiz_DWyXtG_f6WQ&hl=en&ei=9crGS7qlIpK4rAevs53zCQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CAYQ6AEwAA#v=onepage&q=At%20the%20moment%20of%20release%2C%20the%20shot%20is%202.3m%20above%20the%20ground.%20The%20shot%20has%20a%20mass%20of%207.3kg.%20Calculate%20the%20kinetic%20energy%20of%20the%20shot%20at%20the%20moment%20of%20release&f=false

here's the complete question
q 52

T.Q:

--- Quote from: nid404 on April 15, 2010, 08:51:44 am ---This is crazy....I've tried everything to come to the answer!! >:( >:(

Please help

check the attachment for the diagram

At the moment of release, the shot is 2.3m above the ground. The shot has a mass of 7.3kg. Calculate the kinetic energy of the shot at the moment of release....
How on earth is the ans 1713J  am I using the wrong velocity...we're supposed to use the resultant right? in the direction of 12m/s ???

--- End quote ---

the right answer is 713J not 1713J

because K.E=0.5(7.3)(13.97....)^2
            K.E=712.919....... J
           

nid404:
I got the same answer....

But the back of the book says 1713  :(

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