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Maths papers(new format)

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Alpha:

--- Quote from: hotmail16 on April 10, 2010, 08:24:54 pm ---Q..Find any expression, using 1, 2, 3 and n exactly once, which will always be greater than 1 for any
value of n.

--- End quote ---


If you can use n^2,

(n - 3)^2,

n^2 + 3*1,

etc.


--- Quote from: Ari Ben Canaan on April 18, 2010, 02:27:38 pm ---n+1(3-2)

SImple

--- End quote ---

When n <= -1?

Saladin:
I think i hav it, wait a second.

The paper

holtadit:

--- Quote from: ~Alpha on April 18, 2010, 03:28:35 pm ---
If you can use n^2,

(n - 3)^2,

n^2 + 3*1,

etc.

When n <= -1?


--- End quote ---

-1+1(3-2) = 0 Hence 0 is one greater than -1 . Whats the problem ?

Saladin:

--- Quote from: Ari Ben Canaan on April 18, 2010, 04:59:29 pm ----1+1(3-2) = 0 Hence 0 is one greater than -1 . Whats the problem ?

--- End quote ---

it said greater than 1, not negative 1.



Try it with all numbers, it will work.

holtadit:
I just realised he wanted a formula that would give an answer tht is greater than 1

I thought he wanted a formula that would give an answer 1 greater than the value of n


Sorry people, Ari just messed up.... my bad   :-[ :-\

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