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Physics CIE help

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astarmathsandphysics:
No you cant

sweetie:
hey,
cud u help me with Q14, 19, 35 and 36 of nov02 ( AS cie)

astarmathsandphysics:
Will have to be in morning
v late here

astarmathsandphysics:
14 moments about 40 mark 10*100-20*60+50*x=0
1000-1200+50x=0 so x=4
4cm from 40 point going clockwise ie 44cm mark
19.PE=mgh=m*9.8*200=1960m
0.6*1960m=1176m
1/2mv^2=1176m
c^2=2376
v=sqrt(2352)=48.5 C
35.D decreas since more of the voltage is across the variable resistor and nearer to Y cos resistances must remain in proportion
36.2/3V voltage at x is 2/3 and voltage at y is 4/3

sweetie:

--- Quote from: astarmathsandphysics on April 29, 2010, 08:05:29 am ---14 moments about 40 mark 10*100-20*60+50*x=0
1000-1200+50x=0 so x=4
4cm from 40 point going clockwise ie 44cm mark
19.PE=mgh=m*9.8*200=1960m
0.6*1960m=1176m
1/2mv^2=1176m
c^2=2376
v=sqrt(2352)=48.5 C
35.D decreas since more of the voltage is across the variable resistor and nearer to Y cos resistances must remain in proportion
36.2/3V voltage at x is 2/3 and voltage at y is 4/3

--- End quote ---

thanx...
but cud u xplain 14 in more detail??

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