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Physics CIE help

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astarmathsandphysics:
It is 11a) SSince the collision is elastic, separation speed =approach speed
v_b-v_a =u+b+u_a

3ishakay:
How do we do question number 2)c)

in paper 2 .. may/june 09??

2nd variant ppr

halosh92:
paper 2
cie AS physics 2006 nov
Q 3c ii
thx

astarmathsandphysics:
sorry only just noticed this. In morning

astarmathsandphysics:
2c jun 09 p2
impulse =m(v-u)=1.2(-0.8-4))=-5.76
equal and opposite impulse is exerted on 3.6kg mass
so 5.76=m(v-u)=3.6v so v=3.76/3.6=1.6m/s

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