Author Topic: Physics CIE help  (Read 12275 times)

Offline Saladin

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Re: Physics CIE help
« Reply #105 on: May 01, 2010, 05:32:58 pm »
I think the answer is D. Because + the inaccuracy and - the inaccuracy is stll within the 300-350 range. So it is 300.

nid404

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Re: Physics CIE help
« Reply #106 on: May 01, 2010, 05:56:22 pm »
A student makes measurements from which she calculates the speed of sound as 327.66ms–1.
She estimates that her result is accurate to ±3 %.
Which of the following gives her result expressed to the appropriate number of significant figures?
A 327.7ms–1 B 328ms–1 C 330ms–1 D 300ms–1

ok...3% of 227.66 is 9.8 approx 10...so the final answer is rounded off to the nearest 10 which is 330

Offline tmisterr

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Re: Physics CIE help
« Reply #107 on: May 01, 2010, 06:05:12 pm »
thanks nid
 how bout this one? I know the value but how do get the direction?

q36 ATTACHED PAPER

nid404

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Re: Physics CIE help
« Reply #108 on: May 01, 2010, 06:07:35 pm »
field always from positive to negative...so from Q towards P

Offline tmisterr

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Re: Physics CIE help
« Reply #109 on: May 01, 2010, 06:56:05 pm »
how do you know when earthed plate is positive and when it is negative? it confuses me!

nid404

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Re: Physics CIE help
« Reply #110 on: May 01, 2010, 06:58:55 pm »
the other plate is negative, so it is but obv the earthed plate is positive ;)

Offline cashem'up

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Re: Physics CIE help
« Reply #111 on: May 02, 2010, 10:55:51 am »
hey guys i have a doubt in physics mcq november 2005 Q7 can someone please show me how its done

Offline astarmathsandphysics

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Re: Physics CIE help
« Reply #112 on: May 02, 2010, 11:03:22 am »
s_1=1/2at_1^2
s_2=1/2at_2^2
subtrat
h=1/2a(t_2^2-t_1^2)
a=2h/(t_2^2-t_1^2)

Offline tmisterr

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Re: Physics CIE help
« Reply #113 on: May 02, 2010, 02:11:08 pm »
field always from positive to negative...so from Q towards P

Thank you once again

Offline *Hope*

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Re: Physics CIE help
« Reply #114 on: May 03, 2010, 07:15:02 pm »
hey guys! Can u help me out in physics CIE paper1 nov03 Q31? am not able to solve it :-\
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Offline T.Q

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Re: Physics CIE help
« Reply #115 on: May 03, 2010, 07:46:25 pm »
hey guys! Can u help me out in physics CIE paper1 nov03 Q31? am not able to solve it :-\

the total resistance of the circuit is = 4 ohms

find the current across the circuit using I=V/R  I=3A

Find the voltage across 2 ohms resistor  V=6v

SO , the voltage across  3 & 6 ohms resistors are V=6v

using  I=V/R across 6 ohms resistor

I=6/6

I=1A

SO THE ANSWER IS A
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Offline *Hope*

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Re: Physics CIE help
« Reply #116 on: May 04, 2010, 05:33:00 am »
the total resistance of the circuit is = 4 ohms

find the current across the circuit using I=V/R  I=3A

Find the voltage across 2 ohms resistor  V=6v

SO , the voltage across  3 & 6 ohms resistors are V=6v

using  I=V/R across 6 ohms resistor

I=6/6

I=1A

SO THE ANSWER IS A
how did u get 4 ohms in the 1st place?? and can u tell me which paths to take to get the total resistance??
O Allah grant us all the Jannah
Age is an issue of mind over matter. If you don't mind, it doesn't matter
Success is that old ABC ability,breaks,and courage
While there's life,there's Hope ;)
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Keep on forgetting to forget about you <3

Offline T.Q

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Re: Physics CIE help
« Reply #117 on: May 04, 2010, 10:19:36 am »
how did u get 4 ohms in the 1st place?? and can u tell me which paths to take to get the total resistance??

for the parallel resistors  1/3 + 1/6 = 1/R   , 1/R=1/2 , so R=2

now for the series 2+2=4 for the total circuit 
No Matter What Happens In Life , Just Don't Lose Hope :)

Offline *Hope*

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Re: Physics CIE help
« Reply #118 on: May 05, 2010, 06:08:10 am »
for the parallel resistors  1/3 + 1/6 = 1/R   , 1/R=1/2 , so R=2

now for the series 2+2=4 for the total circuit 
Thanks!!TQ
+rep
O Allah grant us all the Jannah
Age is an issue of mind over matter. If you don't mind, it doesn't matter
Success is that old ABC ability,breaks,and courage
While there's life,there's Hope ;)
As long as I have faith in Allah,nothing else matters insA <3
Keep on forgetting to forget about you <3