Qualification > Math

M1 HELP NEEDED, RIGHT NOW!!

<< < (2/7) > >>

mousa:

--- Quote from: nid404 on April 07, 2010, 07:25:39 pm ---Fmax on top box<=1600
F=ma
hence a<=4

P-6000=ma
Pmax-6000=800X4
P=3200+6000
=9200

If there has to be no slipping in the system, both should move together....and that will happen only when they both have the same accn


--- End quote ---

Thank you niddy. :)

nid404:
no prob

halosh92:
could someone answer this plzzz rili urgent :S"
 a stone is dropped from the top of a tower. one second later another stone is throw vertically downwards
from the same point witha velocity of 14m/s .
if theyb hit the ground together find the height of the tower.

thx a ;Dloot

nid404:
assuming the stone is of the same mass

s= ut+1/2 gt2
s=14(t+1)+ 1/2 g(t+1)2
equate the two

ut+1/2 gt2=14(t+1)+ 1/2 g(t+1)2    u=0
So
1/2 gt2=14(t+1)+ 1/2 g(t+1)2
find the value of t
substitute to get s

halosh92:

--- Quote from: nid404 on April 08, 2010, 04:45:40 pm ---assuming the stone is of the same mass

s= ut+1/2 gt2
s=14(t+1)+ 1/2 g(t+1)2
equate the two

ut+1/2 gt2=14(t+1)+ 1/2 g(t+1)2    u=0
So
1/2 gt2=14(t+1)+ 1/2 g(t+1)2
find the value of t
substitute to get s


--- End quote ---
thx a bunch man! life saver u r!

Navigation

[0] Message Index

[#] Next page

[*] Previous page