Qualification > Math

M1 HELP NEEDED, RIGHT NOW!!

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nid404:
also the ms if possible...i'd like to cross check...cuz i do cie

halosh92:
By the way i want to ask u..which one is tougher cie or edexcel?

nid404:

--- Quote from: halosh92 on April 14, 2010, 05:46:26 pm ---By the way i want to ask u..which one is tougher cie or edexcel?

--- End quote ---

I've just solved old M1 edexcel papers...considerably easier I'd say :-\

nid404:
srry for the delay...
glad i ws right  ;D

ok...so basically momentum is a vector quantity so u have to take into the direction of motion

so in collision where momentum is conserved

m1u1+m2u2=m1v1+m2v2

km2u - 4mu = -kmu + mv
v=u(3k - 4)
v>0   that's because k >2  if k>2 then v>+2u implies v>0
change in sign....earlier mometum=? 4mu  now=+u(3k ? 4)  implying change in direction

ok if k=7/3
impulse is the change in momentum
m[u(3k - 4)] - (- 4mu)
3muk-4mu+4mu
3mu X7/3 = 7mu

halosh92:

--- Quote from: nid404 on April 14, 2010, 06:22:53 pm ---srry for the delay...
glad i ws right  ;D

ok...so basically momentum is a vector quantity so u have to take into the direction of motion

so in collision where momentum is conserved

m1u1+m2u2=m1v1+m2v2

km2u ? 4mu = ?kmu + mv
v=u(3k ? 4)
v>0   that's because k >2
change in sign....earlier mometum=? 4mu  now=+u(3k ? 4)  implying change in direction

ok if k=7/3
impulse is the change in momentum
m[u(3k ? 4)] - (? 4mu)
3muk-4mu+4mu
3mu X7/3 = 7mu


--- End quote ---
no problem could you just tell me whats the "?" in ure explanation.....and plz explain this part for me "v>0   that's because k >2"
thx ;D ;D

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