ANY DOUBTS HERE!!!

[Saladin]

Hey u guys, post all ur doubts here, and I will do my best to answer them form u.

Just trying out the tex editor.

[Sue T]

i hope chemistry doubts go here as well
past paper says:

 The equilibrium constant, Kc, for the reaction to form ethyl ethanoate from ethanol and ethanoic
acid, C2H5OH + CH3CO2H CH3CO2C2H5 + H2O, at 60(degree)C is 4.00.
When 1.00 mol each of ethanol and ethanoic acid are allowed to reach equilibrium at 60(degree)C, what
is the number of moles of ethyl ethanoate formed?
A 1/3
B 2/3
C 1/4
D 3/4

[3ishakay]

i hope chemistry doubts go here as well
past paper says:

 The equilibrium constant, Kc, for the reaction to form ethyl ethanoate from ethanol and ethanoic
acid, C2H5OH + CH3CO2H CH3CO2C2H5 + H2O, at 60(degree)C is 4.00.
When 1.00 mol each of ethanol and ethanoic acid are allowed to reach equilibrium at 60(degree)C, what
is the number of moles of ethyl ethanoate formed?
A 1/3
B 2/3
C 1/4
D 3/4

hey ... dyu noe the anser to tht?
wht paper ist frm?

im thinkn the anser is B = 2/3

this is how i did it ..(any1 tell me if i got it wrong .. plz!!)


                      ethanol   +     ethanoic acid    ----->   ethylethanoate   +     water
                      C2H5OH   +    CH3CO2H         ------->  CH3CO2C2H5     +     H2O

b4 eq.                  1                   1                                   0                      0

aftr eq.                1-x                1-x                                 x                       x




thn Kc= [ethylethanoate][water]
            -----------------------
            [ethanol][ethanoic acid]


so its like  


          [ x]^2           =  4
        --------
          [1-x]^2


thn u ju solv it like in maths ..

and thn u get 2/3 =D

rechek the smae crap..


go


           ( 2/3)^2              =    4!!   TADA!!! :D:D
          ----------
            (1/3)^2

[nid404]

hey Thanks

[3ishakay]

hey Thanks

not a prbm     

[ruby92]

the answer is b???

[nid404]

the answer is b???

U have doubts??
Wait, I'll check her post agn

[ruby92]

lool no...i get it..i was checking i didnt read 3ishakay post 

[3ishakay]

lool no...i get it..i was checking i didnt read 3ishakay post 

lol cool ..

By the way im not sure abt my post .
i always use the revers method cus its fastr.

im not evn sure if the math bit turns out ryt ..

[nid404]

Yup she's right

[halosh92]

PHYSICS AS
could u just explain how to solve this question step by step please?

Jill is swimming across a river which has  constant current of "k m/s". if jill heads directly across the river with speed "v m/s"
find her resultant speed and the angle her path makes with a line directly across the river when
k= 2
v=1
 thx alot

[Saladin]

really sorry u guys, my electricity was out, so i cud not ansa.

[Saladin]

PHYSICS AS
could u just explain how to solve this question step by step please?

Jill is swimming across a river which has  constant current of "k m/s". if jill heads directly across the river with speed "v m/s"
find her resultant speed and the angle her path makes with a line directly across the river when
k= 2
v=1
 thx alot

this is a simple trigonometric question.

electricity going again

srry cud not reply

cant scan the thing

will wen i can

thanks


hope u guys dnt mind.

[Sue T]

4got 2 mention th answer was b
thanx!

[nid404]

PHYSICS AS
could u just explain how to solve this question step by step please?

Jill is swimming across a river which has  constant current of "k m/s". if jill heads directly across the river with speed "v m/s"
find her resultant speed and the angle her path makes with a line directly across the river when
k= 2
v=1
 thx alot

R= root of k2 + v2
= root of 5

tan theta= k/v=2
theta= 63.43^o clockwise  down the stream