Qualification > Queries
ANY DOUBTS HERE!!!
halosh92:
--- Quote from: ~ A.F ~ on May 29, 2010, 07:01:26 pm ---Please post the question paper here halosh :)
--- End quote ---
sure
and could u do these as well plz same paper:
3bi .....why is the angle 90 ?
5b
7aii,7aiii
2nd variant:
Q7a
thankyouuuuuuu
Meticulous:
--- Quote from: halosh92 on May 29, 2010, 05:35:04 pm ---physics cie AS
p2 june 2009
variant 1
Q2c, d
for 'c" shouldnt it be -1.6 ???
and for "d"......wats the formula for speed of separation and speed of approach? and do we take the signs into account?
--- End quote ---
c) it will move in the initial direction, which is positive! u see, the MAGNITUDE of force is the same in both, but the direction of force and impulse varies.
d) equation is: u1 - u2 = v2 - v1 = -(v1 -v2 )and yes you do take signs into account
halosh92:
--- Quote from: ~ A.F ~ on May 29, 2010, 08:55:30 pm ---c) it will move in the initial direction, which is positive! u see, the MAGNITUDE of force is the same in both, but the direction of force and impulse varies.
d) equation is: u1 - u2 = v2 - v1 = -(v1 -v2 )and yes you do take signs into account
--- End quote ---
thankyou ;D
and could u plz solve the rest?
:)
nid404:
--- Quote from: halosh92 on May 29, 2010, 08:02:53 pm ---sure
and could u do these as well plz same paper:
3bi .....why is the angle 90 ?
5b
7aii,7aiii
--- End quote ---
3) b) max value of the function cosx is 1
cos 90=1
max turning effect when theta=90 :)
5b) there is a formula u need to know
phase difference=( 2pi/ lamda) X path difference
phase difference = pi [ for destructive interference]
lambda(wavelength) = 2pi/ pi X path difference.
path difference is S2M - S1M
find S2M using Pythagoras = root of 802 + 1002
=128
path difference= 128-100=28
wavelength= 2pi/pi X 28
=56cm
At f= 1KHz wavelength= 0.33m/ 33cm
At f=4kHz wavelength= 0..0825/8.25cm
wavelength changes from 33cm to 8.25cm
for minima...phase difference should be either one of them pi, 3pi,5pi,7pi [sub them in the eqn]
minima is observed when lambda= 56cm, 18.7cm, 11.2cm, 8cm
which are the 2 values between 33 and 8.25?? 18.7 and 11.2...so only 2 minimas
7)a)
ii) R between BX implies combined resistance of two parallel resistors in the loop BYCX = R/2
iii) AZ will be the combined resistance of all.
R in BY and CX are paralle...their combined value is R/2 this is in series with 2 more resistors.
So combined resistance = R/2 + 2R = 2.5R
halosh92:
--- Quote from: nid404 on May 30, 2010, 05:59:15 am ---3) b) max value of the function cosx is 1
cos 90=1
max turning effect when theta=90 :)
5b) there is a formula u need to know
phase difference=( 2pi/ lamda) X path difference
phase difference = pi [ for destructive interference]
lambda(wavelength) = 2pi/ pi X path difference.
path difference is S2M - S1M
find S2M using Pythagoras = root of 802 + 1002
=128
path difference= 128-100=28
wavelength= 2pi/pi X 28
=56cm
At f= 1KHz wavelength= 0.33m/ 33cm
At f=4kHz wavelength= 0..0825/8.25cm
wavelength changes from 33cm to 8.25cm
for minima...phase difference should be either one of them pi, 3pi,5pi,7pi [sub them in the eqn]
minima is observed when lambda= 56cm, 18.7cm, 11.2cm, 8cm
which are the 2 values between 33 and 8.25?? 18.7 and 11.2...so only 2 minimas
7)a)
ii) R between BX implies combined resistance of two parallel resistors in the loop BYCX = R/2
iii) AZ will be the combined resistance of all.
R in BY and CX are paralle...their combined value is R/2 this is in series with 2 more resistors.
So combined resistance = R/2 + 2R = 2.5R
--- End quote ---
thankyou so much !!! but for the 5b........wat do we do if its constructive interference? and when do we exactly use that formula u gave, when we have to combine phase difference and path difference??
thxxx
and could u do the 2nd variant of the paper:
Q7a (with details) thxxxx alooot
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