Qualification > Queries

ANY DOUBTS HERE!!!

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The SMA:

--- Quote from: nid404 on May 28, 2010, 02:52:51 pm ---Optical isomer are possible only in compounds containing a chiral carbon

So it's not possible in the first one.

Here's how the second one would look

--- End quote ---

nid is there a step/rule on arranging the atoms/groups? whether CH3- group or something else
should be on top the chiral Carbon atom [im taking the second problem H3C-CBr(COOH)-CH2Br as e.g ]

most of my answers for the question of this type does not seem to be similar to the Marking Scheme.
They put something different on top or at any other place. If i don't get the same arrangement as MS
will i be losing marks? :S

nid404:

--- Quote from: The SMA on May 29, 2010, 07:40:45 am ---nid is there a step/rule on arranging the atoms/groups? whether CH3- group or something else
should be on top the chiral Carbon atom [im taking the second problem H3C-CBr(COOH)-CH2Br as e.g ]

most of my answers for the question of this type does not seem to be similar to the Marking Scheme.
They put something different on top or at any other place. If i don't get the same arrangement as MS
will i be losing marks? :S

--- End quote ---

I'm really not getting you :/ Rule in arranging? You simply reflect the compound...like you reflect something in a mirror.

the arrangement doesn't matter in this particular case...just that COOH and Br are side chains.

The SMA:
oh okay. thanks nid! ^^

halosh92:
physics cie AS
p2 june 2009
variant 1
Q2c, d
for 'c" shouldnt it be -1.6 ???
and for "d"......wats the formula for speed of separation and speed of approach? and do we take the signs into account?

Meticulous:
Please post the question paper here halosh :)

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