Qualification > Queries

ANY DOUBTS HERE!!!

<< < (36/58) > >>

nid404:

--- Quote from: A@di on May 28, 2010, 12:48:41 pm ---ok sry, i didnt put the q rite, it says by resolving horizontally show that the T in the shorter chain is 48N! not 27N

plus, the mass is 6kg :-/

--- End quote ---

ok then...refer to the same diagram

a=53.13
b=36.87

now 36cos36.87=Tcos53.13
T=48 N

now resolve vertically
36sin36.87+48sin53.13=mg
  21.6    +38.4=mg
60=mg
m=6kg

Ghost Of Highbury:
Okay, i tried that and i got it. But what puzzles me is the previous method u used, that is also a correct way to find the force rite?

F = 27N ?

By the way, thanks for the other answers..! :)

nid404:

--- Quote from: A@di on May 28, 2010, 12:57:37 pm ---Okay, i tried that and i got it. But what puzzles me is the previous method u used, that is also a correct way to find the force rite?

F = 27N ?

By the way, thanks for the other answers..! :)

--- End quote ---

I am wondering...cause i used something similar in another question like this is the book...and got the right ans....I must check tho  :-\

You're welcome  ;)

The SMA:
guys juz a short question on chemistry AS,
how do you arrange atoms/groups in an optical isomerism
for e.g (i) CH3COCOOH (ii) H3C-CBr(COOH)-CH2Br

if you could xplain in diagram it will be very much appreciated ^^

nid404:
Optical isomer are possible only in compounds containing a chiral carbon

So it's not possible in the first one.

Here's how the second one would look

Navigation

[0] Message Index

[#] Next page

[*] Previous page