ALL PHYSICS DOUBTS - POST HERE !!

[the_grim_reaper]

I understand the system, but when it comes to the 'latch'... i dont understand sh*t I was absent when teacher explained it, told her to explain it to me, she told me not my problem 0.0 -.- Tried to understand myself... well how can i understand anything in the Collin's f**ked up book

My teacher never heard the name. I didn't know it till reading collins. By the way, anyone knows how a bridge rectifier works!!! I'm getting really nervous here

[pglasg74]

Converging Lens

Object between F and Optical Centre - Virtual, Upright and Larger than the object.
Object between F and 2F - Real, Inverted and Larger than the object.
Object at 2F - Real, Inverted, Same size as the object.
Object beyond 2F - Real, Inverted and Smaller than the object.

can u please help me with my qs? i posted it on this page or the last page? please thanxx!

[diva_sparkles]

can any 1 plz explain de ticker timmer stuff for de acceleration

Ticker-tape =  http://www.physicsphenomena.com/TickerTape.html
    http://www.practicalphysics.org/go/Experiment_310.html

[Syed Kazim]

i wnt thru dem dey wer vre hlpful!!!!

Glad I could help.

[NidZ- Hero]

u mean ticker tape?? dats not in de portion!!

noo it is it came in 2008 o/n p3

[blackberry]

noo it is it came in 2008 o/n p3

firstly its not in de syllabus!!!(i jus checked)!!
secondly o/n papers are harder nd kinda moe extensive than the m/j ones we do cuz if u see sum questions you wont understand it so well(im talking generallly)!!
thirdly o/n is mostly for those hoo do igcse outside of skool!!
see?

[Syed Kazim]

can someone help and attach a drawing of 8a please

http://www.freeexampapers.us/IGCSE/Physics/CIE/2007%20Jun/0625_s07_qp_3.pdf

EDIT: I forgot to put the A in the ammeter. Please do label it in the exam.

[Ivo]

Ivo you can't always find the distance using the average. If it isn't available, use a different formula. Here, my teacher taught me a very good one which can be used. Its distance=(initial speed)xtime+ 0.5(mass)(final velocity)^2 (squaring on final velocity). Pluck in the values and you'll get the right answer.

In case of forces, if in equilibrium, sum of forces in one direction is equal to sum of forces in other direction. Here downward forces (due to weights) AND the disc have to be used (the disc will also be pulled by gravity). The poor pivot will have to balance all of em'

For 5 c, I've got no idea. Shazzizle gave an odd explanation on Page 137.

For 8, it's series. In parallel they'll light with full brightness (since each gets the mains voltage, current blah blah). In series it's normal brightness.

For 9, the easiest idea is to pump water higher. It's almost in every text book. No capacitors since they can't be charged with AC (Thanks VIN!!!!!!)

Thanks, you're amazing!  By the way, for the pump water higher, how does it work, I still don't get that bit.

By the way, for the formula you're teacher told u is distance (s) = 0.5(u+v)t

[pglasg74]

EDIT: I forgot to put the A in the ammeter. Please do label it in the exam.

omg thanks ur an angel.. i had 2 more qs though.. i think its 2007 but u know the question with the magnet and the wheel that turns? if not i plosted it a few pages ago.. umm ok tehy ask to find the driection of wheel turning, so my index pointed right, my current towards me and consequently my thumb pointed up.. which means clockwise idk how to get anticlockwise (the answer is anti)

and can u pls copy paste the image properties thankss

[pglasg74]

EDIT: I forgot to put the A in the ammeter. Please do label it in the exam.

its number 9 in teh same paper.. 2007 mj.. thanks a loooot

and also http://www.freeexampapers.us/IGCSE/Physics/CIE/2005%20Nov/0625_w05_qp_3.pdf

q7 why is the eye to the right of the lens? can u tell me the image prop rules please thanks syed!

[diva_sparkles]

    gud luck 4 physics exm!!!

[Syed Kazim]

omg thanks ur an angel.. i had 2 more qs though.. i think its 2007 but u know the question with the magnet and the wheel that turns? if not i plosted it a few pages ago.. umm ok tehy ask to find the driection of wheel turning, so my index pointed right, my current towards me and consequently my thumb pointed up.. which means clockwise idk how to get anticlockwise (the answer is anti)

and can u pls copy paste the image properties thankss

I think this is what you meant by image properties:
Converging Lens

Object between F and Optical Centre - Virtual, Upright and Larger than the object.
Object between F and 2F - Real, Inverted and Larger than the object.
Object at 2F - Real, Inverted, Same size as the object.
Object beyond 2F - Real, Inverted and Smaller than the object.


About that question:

http://www.freeexampapers.us/IGCSE/Physics/CIE/2007%20Jun/0625_s07_qp_3.pdf


someone please tell me why number 9 its anticlockwise.. if i used FLH, my index points right,

Give me a few minutes please... let me figure it out.

[6394]

I think this is what you meant by image properties:
Converging Lens

Object between F and Optical Centre - Virtual, Upright and Larger than the object.
Object between F and 2F - Real, Inverted and Larger than the object.
Object at 2F - Real, Inverted, Same size as the object.
Object beyond 2F - Real, Inverted and Smaller than the object.


About that question:
Give me a few minutes please... let me figure it out.

where do u live
r u givin xam in mornin?

[Ivo]

its number 9 in teh same paper.. 2007 mj.. thanks a loooot

and also http://www.freeexampapers.us/IGCSE/Physics/CIE/2005%20Nov/0625_w05_qp_3.pdf

q7 why is the eye to the right of the lens? can u tell me the image prop rules please thanks syed!

Here is my diagram in response to your question.  Hope this helps

[Syed Kazim]

its number 9 in teh same paper.. 2007 mj.. thanks a loooot

and also http://www.freeexampapers.us/IGCSE/Physics/CIE/2005%20Nov/0625_w05_qp_3.pdf

q7 why is the eye to the right of the lens? can u tell me the image prop rules please thanks syed!

The distance of the object from the mirror (A in this case) must be equal to the distance of the mirror to the image (B in this case). Also, they must form in a straight line.