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[Shazizzzle]

Wat about the iii part...predicting the value...?

The ratio is to remain the same in all.
It'll also be 2.5-ish or around.
Same as the upper two values.

[Malak]

using the graph you've made, you take the corresponding values of the time taken, at 20 deg. c, and at 30 deg. C, from the graph, and you take their ratio.
I.e., draw a dotted line from 20 deg c, where the line meets the curve, continue on to the y axis and use the value you get.
Simple division.

You will see the ratio of 20/30 and 40/50 is increasing by a set interval.
use that interval to predict the answer of 50/60.

Oh get it Thanks

[6394]

@ adzel wat do u do aftr placing the pin horizontly on 10 cm on the scale n
some 1 plz telme this: wen dey ask ask us to draw graph wid x axis startin frm 0.1 n y axis startin from 10 den do we have 2 put dese zigzag thingy ??

[Shazizzzle]

Divide the change in Y value by the change in x value

That is, draw the traingle.
then use two points A & B.
And apply the same formula!

[6394]

sry 84.2 cm

[Shazizzzle]

@ adzel wat do u do aftr placing the pin horizontly on 10 cm on the scale n
some 1 plz telme this: wen dey ask ask us to draw graph wid x axis startin frm 0.1 n y axis startin from 10 den do we have 2 put dese zigzag thingy ??

That zig zag thing is called a 'break'.
It is NOT required for physics.
Only in maths.
As they've made the grid already.

[Adzel]

Because the marking scheme says it different

The answer in the markscheme is :-

• Readings taken at either side/diameter of cylinder
• Position of mid point found
• Mark position of centre

This is correct then;

[red_911]

hey please help me in june 2007 question 3(b)1 .. how is R propotional to 1/d square ?
and
also in june 2005 question 4(c) ask about T being proptional to m .. but the mark scheme says that the answer is "NO" as T/m increases as m decreases ..why do we have to take T/m  

plzz any1 answer my questions 

[Shazizzzle]

plzz any1 answer my questions 

The resistance of AB is 7.92.
Of CD: 1.98.

Now, the diameter of CD TWICE of AB.
however, the resistance is not HALF of AB. The resistance is ONE FOURTH i.e ONE QUARTER of Ab.
If it were half of AB, then it would be proportional to 1/d.
as it is ONE FOURTH, it is proportional to 1/d^2.

[6394]

@ adzel cud u explain wen n hw do u do dat pin method??
loadz Thanks

[6394]

detaild explanation plzzz!!!!!!

[red_911]

The resistance of AB is 7.92.
Of CD: 1.98.

Now, the diameter of CD TWICE of AB.
however, the resistance is not HALF of AB. The resistance is ONE FOURTH i.e ONE QUARTER of Ab.
If it were half of AB, then it would be proportional to 1/d.
as it is ONE FOURTH, it is proportional to 1/d^2.

thanks alot ... do u know asnwer to my other question ?

[Shazizzzle]

plzz any1 answer my questions 

Although T is dropping as M does, the interval between the consecutive Ts are not the same.
To be proportional, there needs to be drop by a constant value, K. A set interval.
here, however, it first shows a deep drop from 0.9 to 0.78. Then 0.73 a short drop to 0.63.
the intervals have to be a fixed ratio.

True, I'm confused of why the mark scheme mentioned T/m. :S

Oh yes. To be directly proportional... the ratio also has to be increasing.
i.e T/m should also increase as m does. I think. :S

[Mathewness]

November 2005 Paper 6
Question 2, (c)

How do you do that?

[red_911]

November 2005 Paper 6
Question 2, (c)

How do you do that?

4+1.978=5.978 aprox. 6 .... resistance of wire ab and ac is added ...