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blackberry:

--- Quote from: Nidzzz on May 26, 2010, 11:13:52 pm ---noo it is it came in 2008 o/n p3

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firstly its not in de syllabus!!!(i jus checked)!!
secondly o/n papers are harder nd kinda moe extensive than the m/j ones we do cuz if u see sum questions you wont understand it so well(im talking generallly)!!
thirdly o/n is mostly for those hoo do igcse outside of skool!!
see? 8)

Syed Kazim:

--- Quote from: pglasg74 on May 26, 2010, 10:29:45 pm ---can someone help and attach a drawing of 8a please :(

http://www.freeexampapers.us/IGCSE/Physics/CIE/2007%20Jun/0625_s07_qp_3.pdf

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EDIT: I forgot to put the A in the ammeter. Please do label it in the exam.

Ivo:

--- Quote from: deadman786 on May 26, 2010, 11:04:48 pm ---
Ivo you can't always find the distance using the average. If it isn't available, use a different formula. Here, my teacher taught me a very good one which can be used. Its distance=(initial speed)xtime+ 0.5(mass)(final velocity)^2 (squaring on final velocity). Pluck in the values and you'll get the right answer.

In case of forces, if in equilibrium, sum of forces in one direction is equal to sum of forces in other direction. Here downward forces (due to weights) AND the disc have to be used (the disc will also be pulled by gravity). The poor pivot will have to balance all of em'

For 5 c, I've got no idea. Shazzizle gave an odd explanation on Page 137.

For 8, it's series. In parallel they'll light with full brightness (since each gets the mains voltage, current blah blah). In series it's normal brightness.

For 9, the easiest idea is to pump water higher. It's almost in every text book. No capacitors since they can't be charged with AC (Thanks VIN!!!!!!)

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Thanks, you're amazing!  By the way, for the pump water higher, how does it work, I still don't get that bit.

By the way, for the formula you're teacher told u is distance (s) = 0.5(u+v)t

pglasg74:

--- Quote from: Syed Kazim on May 26, 2010, 11:25:10 pm ---EDIT: I forgot to put the A in the ammeter. Please do label it in the exam.

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omg thanks ur an angel.. i had 2 more qs though.. i think its 2007 but u know the question with the magnet and the wheel that turns? if not i plosted it a few pages ago.. umm ok tehy ask to find the driection of wheel turning, so my index pointed right, my current towards me and consequently my thumb pointed up.. which means clockwise idk how to get anticlockwise (the answer is anti)

and can u pls copy paste the image properties thankss

pglasg74:

--- Quote from: Syed Kazim on May 26, 2010, 11:25:10 pm ---EDIT: I forgot to put the A in the ammeter. Please do label it in the exam.

--- End quote ---

its number 9 in teh same paper.. 2007 mj.. thanks a loooot :)

and also http://www.freeexampapers.us/IGCSE/Physics/CIE/2005%20Nov/0625_w05_qp_3.pdf

q7 why is the eye to the right of the lens? can u tell me the image prop rules please thanks syed!

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