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Weaam:
Also can i get the answer to o/n 08 Q5 c(i) second varient!
Thanks!

Ghost Of Highbury:

--- Quote from: weaam on May 26, 2010, 08:37:37 pm ---Also can i get the answer to o/n 08 Q5 c(i) second varient!
Thanks!

--- End quote ---

Please provide the links next time you ask a doubt, thank you :D

ill answer this one..

Malak:
http://www.freeexampapers.us/IGCSE/Physics/CIE/2009%20Nov/0625_w09_qp_31.pdf

Q11 part c n onwards..

thx

Vin:

--- Quote from: ang3l on May 26, 2010, 08:23:06 pm ---http://www.freeexampapers.us/IGCSE/Physics/CIE/2009%20Nov/0625_w09_qp_31.pdf

Q11 part c nd so on the rest

thx


--- Quote from: ang3l on May 26, 2010, 08:40:32 pm ---http://www.freeexampapers.us/IGCSE/Physics/CIE/2009%20Nov/0625_w09_qp_31.pdf

Q11 part c n onwards..

thx

--- End quote ---

--- End quote ---


11 a) A- NOT gate B- AND

b) dark and cold  = low light and low temp

Output of A = High
Output of B = Low

ii) dark and warm = low light and high temp.

Output of A = High
Output of B = High

iii) bright and warm = high light and hig temp.

Output of A = Low
Output of B = Low

c) i) Here the relay can be used to increase the current because the output of B is low .. Relay connects two circuits has its own power supply this supply is given as the output of the relay .. the output of B is enough to magnetize the iron in the relay which closes the contacts and supplies outout current  (hope u know the structure of a relay so u'll get what im talking about .. in this question u dont have to answer this much ..)

ii) its b) ii) because its the only B output that is high

iii) In a fridge .. it has a closed environment and this type of circuit works in a compact/dark environment

Ghost Of Highbury:

--- Quote from: A@di on May 26, 2010, 08:38:57 pm ---Please provide the links next time you ask a doubt, thank you :D

ill answer this one..

--- End quote ---

3 minuts = 180s

energy = 40*180 = 7200J

change in temp = 5.9
250g = 0.25Kg
E = m*c*t

7200/0.25*5.9 = 4881J/kgK

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