Qualification > Sciences
ALL PHYSICS DOUBTS - POST HERE !!
$H00t!N& $t@r:
A laboratory determination of the specific latent heat of vaporisation of water uses a 120W heater to keep water boiling at its boiling point. Water is turned into steam at the rate of 0.050 g/s.
Calculate the value of the specific latent heat of vaporisation obtained from this experiment. Show your working.
Vin:
--- Quote from: Shooting Star on May 07, 2010, 07:04:55 pm ---A laboratory determination of the specific latent heat of vaporisation of water uses a 120W heater to keep water boiling at its boiling point. Water is turned into steam at the rate of 0.050 g/s.
Calculate the value of the specific latent heat of vaporisation obtained from this experiment. Show your working.
--- End quote ---
P= 120 W
Heat (Q) = 120 J/s
mass = 0.05 g/s
Q = mL
L= 120/0.05
= 2400 J/g
this should be right..:)
$H00t!N& $t@r:
--- Quote from: ~VIN1094~ on May 07, 2010, 07:17:22 pm ---P= 120 W
Heat (Q) = 120 J/s
mass = 0.05 g/s
Q = mL
L= 120/0.05
= 2400 J/g
this should be right..:)
--- End quote ---
Thanks this is the answer in d ms. the thing I was confuse with is when they said: Water is turned into steam at a rate of 0.050 g/s. I thought they meant speed. So I ws wondering how to calculate that. But hw is 0.050 g/s the mass?
Snake:
Guys what was the transformer formula? Np/Ns=Vp/Vs=Ip/Is?
Vin:
see the thing here is, as u said they hav given the "mass" as 0.05g per second .. here i didnt literally mean it as 'mass' .. it was jus for ur understanding u kno..:)
but did u get the concept ??
/ sec cancels out in the equation .. ;)
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version