Qualification > Sciences
ALL PHYSICS DOUBTS - POST HERE !!
Ghost Of Highbury:
--- Quote from: Kimo Jesus on May 24, 2010, 06:14:21 pm ---http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/imgmag/magcur.gif
[/quote
ok try this, make ur fingers as shown in the diagram...the way the fingers are wrapped around show how the magnetic lines will be...
check the diagram..check the red arrows which indicate the magnetic field an and direction..
only the red arrow near C matches the compass arrow..
--- End quote ---
WARRIOR:
--- Quote from: A@di on May 24, 2010, 06:54:11 pm ---
--- Quote from: Kimo Jesus on May 24, 2010, 06:14:21 pm ---http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/imgmag/magcur.gif
[/quote
ok try this, make ur fingers as shown in the diagram...the way the fingers are wrapped around show how the magnetic lines will be...
check the diagram..check the red arrows which indicate the magnetic field an and direction..
only the red arrow near C matches the compass arrow..
--- End quote ---
aadi can u explain to me why the barometers diamter doest affect height? i kno by heart that it doesnt..but for what reason exactly..( dont say the area doesnt affcet height :P or say with with a good reason :P)
--- End quote ---
Malak:
--- Quote from: A@di on May 24, 2010, 06:54:11 pm ---
--- End quote ---
--- Quote from: Kimo Jesus on May 24, 2010, 06:14:21 pm ---http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/imgmag/magcur.gif
ok try this, make ur fingers as shown in the diagram...the way the fingers are wrapped around show how the magnetic lines will be...
check the diagram..check the red arrows which indicate the magnetic field an and direction..
only the red arrow near C matches the compass arrow..
--- End quote ---
Get it now..Thx :D
Ghost Of Highbury:
--- Quote from: Kimo Jesus on May 24, 2010, 07:07:09 pm ---aadi can u explain to me why the barometers diamter doest affect height? i kno by heart that it doesnt..but for what reason exactly..( dont say the area doesnt affcet height :P or say with with a good reason :P)
--- End quote ---
ok here
The weight mercury in the barometer = AHdg,
where 'A' = area of cross-section
H' is the height of the mercury column
d is the density
g is the acceleration due to gravity = 9.8 m/s^2
But the pressure p is the weight per unit area.
So if you divide AHdg by 'A' you get p=Hdg i.e p = height*density*acc. due to gravity
You can now notice that the pressure is independent of the value of the cross-sectional area ((diamter/2)^2 * pi)
WARRIOR:
--- Quote from: A@di on May 24, 2010, 07:16:59 pm ---ok here
The weight mercury in the barometer = AHdg,
where 'A' = area of cross-section
H' is the height of the mercury column
d is the density
g is the acceleration due to gravity = 9.8 m/s^2
But the pressure p is the weight per unit area.
So if you divide AHdg by 'A' you get p=Hdg i.e p = height*density*acc. due to gravity
You can now notice that the pressure is independent of the value of the cross-sectional area ((diamter/2)^2 * pi)
--- End quote ---
i seeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee !
thanks man uv been really helpful !
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