Qualification > Math
m1 urgent doubt :/
sweetest angel:
Two forces, (4i – 5j) N and (pi + qj) N, act on a particle P of mass m kg. The resultant
of the two forces is R. Given that R acts in a direction which is parallel to the
vector (i – 2j),
(a) find the angle between R and the vector j,
(b) show that 2p + q + 3 = 0.
Given also that q = 1 and that P moves with an acceleration of magnitude 8?5 m s–2,
(c) find the value of m.
i need someone to xplain part b asap...Thanks :)
halosh92:
--- Quote from: sweetest angel on March 28, 2010, 04:54:04 pm ---Two forces, (4i – 5j) N and (pi + qj) N, act on a particle P of mass m kg. The resultant
of the two forces is R. Given that R acts in a direction which is parallel to the
vector (i – 2j),
(a) find the angle between R and the vector j,
(b) show that 2p + q + 3 = 0.
Given also that q = 1 and that P moves with an acceleration of magnitude 8?5 m s–2,
(c) find the value of m.
i need someone to xplain part b asap...Thanks :)
--- End quote ---
how did u do part a?
sweetest angel:
tan? = 2/1
?? = 63.4
angle is 90+63.4=153.4
its because it is parallel to (i-2j) so they'l have the same angel
bdw its 2laa2 ya halla :)
Phosu:
b part, add the 2 vector forces to give the resultant force
the resultant force vector is parallel to the (i-2j) vector, hence gradient will be same
formula is i1/i2 = j1/j2
Ri /i = Rj /-2
4+p/1= q-5/-2
cross multiply to get
halosh92:
--- Quote from: sweetest angel on March 28, 2010, 05:16:32 pm ---tan? = 2/1
?? = 63.4
angle is 90+63.4=153.4
its because it is parallel to (i-2j) so they'l have the same angel
bdw its 2laa2 ya halla :)
--- End quote ---
hahhaah mana 3arfa ya otah ;)
thx..am failing mechanics tomorrow -.-"
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