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astarmathsandphysics:
Distance frim S_2 to M is sqrt(1^2 +0,8^)=1.28m
so path difference =0.28m
when f=1kHz wavelength=v/f=330/1000=0.33
When f=4kHz wavelength=330/4000=0.0825
minumum whenw/2=28 or 3w/2 =28 or 5w/2=28 or 7w/2 =28
w=56 or w=18.7 or w=11.2 or w=8
only two of these are between 8.25 and 33
so only two minima

AN10:
ok....thanx a lot!!

halosh92:

--- Quote from: astarmathsandphysics on March 22, 2010, 12:32:45 pm ---Distance frim S_2 to M is sqrt(1^2 +0,8^)=1.28m
so path difference =0.28m
when f=1kHz wavelength=v/f=330/1000=0.33
When f=4kHz wavelength=330/4000=0.0825
minumum whenw/2=28 or 3w/2 =28 or 5w/2=28 or 7w/2 =28
w=56 or w=18.7 or w=11.2 or w=8
only two of these are between 8.25 and 33
so only two minima

--- End quote ---

i dont get this part only:
minumum whenw/2=28 or 3w/2 =28 or 5w/2=28 or 7w/2 =28

astarmathsandphysics:
w is the wavelenfth and mimima where paths difference  is w/2 or 3w/2 etc

astarmathsandphysics:
cos that means destructive interference

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