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PHYSICS AS HELP

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~Mimi~:
googled stuff. Is this of any help whatsoever:

Uniform electric fields
What do we mean by a “uniform” field? (One that does not vary from place to place. In terms of the field lines, this means that they are parallel and evenly spaced. Also as field strength = – (potential gradient), the equipotentials should also be evenly spaced.)
Where have we seen such as field? (The field between two parallel charged plates.)
 
How will a charge move in such a field? (The force is given by
F = EQ
Since E is constant, the force will be constant and therefore, by
F = ma
the acceleration will also be constant and directed along the field lines for a positive charge and opposite to the field lines for a negative charge. (Note: A constant acceleration produces a parabolic path for the charge if it has any component of motion across the field lines, just as with projectiles in the Earth’s constant gravitational field near its surface)."

 

nid404:
yaa but why is E constant is the question :(

thanks for helping tho :)

~Mimi~:
May/June 2004. Question 27.
 I guess it's just estimation.
speed of light : 3 x 10^ 8 m/s
wavelength of infrared : 1000 nm to 100000 nm approx.  (let's assume, you've studied approximate wavelengths of the different radiations)
use v= f x wavelength
3 x 10^14 and 3 x 10^12.....the values u get for frequency for the wavelengths mentioned above. So, I guess it's ,safely, C.

However , I do hope someone can suggest a much simpler way, sans calculation, hopefully...

halosh92:

--- Quote from: ~~Muslimah93~~ on March 21, 2010, 03:23:30 pm ---May/June 2004. Question 27.
 I guess it's just estimation.
speed of light : 3 x 10^ 8 m/s
wavelength of infrared : 1000 nm to 100000 nm approx.  (let's assume, you've studied approximate wavelengths of the different radiations)
use v= f x wavelength
3 x 10^14 and 3 x 10^12.....the values u get for frequency for the wavelengths mentioned above. So, I guess it's ,safely, C.

However , I do hope someone can suggest a much simpler way, sans calculation, hopefully...

--- End quote ---

 i rili dont get the part where u substituted the velocity with 3 x 10^14
isnt it supposed to be 3 x 10^ 8 m/s
and how did u get 3 x 10^12
thxxx

halosh92:
nov 2003
cie
physics AS


Q4
Q8 (explanation)
Q11
Q12
Q14
Q16
Q24
Q28

VERY URGENT! PLZ

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