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ruby92:
may june 2009 paper 1 no 28
no 22 hw is it free radical substitution (d) shouldn't it be B??
and no 29

ruby92:
May june 2009 p2
Q4 part (a) the C and D box

nid404:
June 09 paper 1
Q22) It's free radical substitution...
cause Cl radicals react with ethanoic acid.
And it can't be A and B at all cause Cl-  would be a nucleophile(nucleus loving) and not an electrophile...

Q28) 2,4 DNP reacts with carbonyls (C=O)
there's one already present
on adding acidified potassium manganate(which is an oxidising agent), it will form CO2 and COOH wherever there is a carbon-carbon double bond....
I'm sorry I couldn't explain this properly...will try looking for the compound after oxidising...so ull understand better

Q29)2-Methylbuta-1,3-diene, CH2=C(CH3)–CH=CH2 contains 5 carbons, 8 hydrogens and no oxygens
H2SO4 is a dehydrating agent...it removes water from the compound
A,B,C give rise to the monomer when water is removed
 As for D, when water is removed it doesn't hydroxyl group is secondary....it's an isomer of the monomer required

nid404:
I'll answer the others in a while...i gtg nw

ruby92:
could you please explain 29 again....
i really dont get it

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