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maths c2 edexcel

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astarmathsandphysics:
for the a and b tan questions find any answer to tanx=c then keep adding 180

sinx=0 x=-360,-180,0,180,360

2cos x=3 sinx so tanx=2/3 so x=33.7,180+33.7,360+33.7 etc

Can you post the very first question with all the squares made clear

halosh92:

--- Quote from: astarmathsandphysics on March 14, 2010, 09:34:24 am ---for the a and b tan questions find any answer to tanx=c then keep adding 180

sinx=0 x=-360,-180,0,180,360

2cos x=3 sinx so tanx=2/3 so x=33.7,180+33.7,360+33.7 etc

Can you post the very first question with all the squares made clear

--- End quote ---

for any tan questions !!-do we ALWAYS add 180???

astarmathsandphysics:
yes always add 180
http://www.astarmathsandphysics.com/a_level_maths_notes/C3/a_level_maths_notes_c3_finding_multiple_solutions_of_trigonometric_equations.html

halosh92:
okay thx alot  ;D ;D ;D ;D

binomial expansion :

(when (1-3/2 x)^p is expanded in ascending powers of "x" , the coefficient of "x" is -24
a) find the value of "p"
b) find the coefficient of x^2 in the expansion
c) find the coefficient of x^3 in the expansion

astarmathsandphysics:
(1-3x/2)^p =1+(-3px/2)+(p(p-1)/2!*(-3x/2)^2+(p(p-1)(p-2)/3!)(-3x/2)^3+....
-3p/2=-24 so p=16
coefficienct of x^2 (p(p-1)/2!*(-3/2)^2 =(16(16-1)/2!*(-3/2)^2 =270
coefficient of x^3 (p(p-1)(p-2)/3!)(-3/2)^3 =(16(16-1)(16-2)/3!)(-3/2)^3 =1260

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