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The roots are at x=0,2,5Exapnd the brackets to get Integrate beteen the roots in two partsthe minus in the second integral is there because the graph is below the axisWe have=16/3+125/12+16/3=253/12
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![[\frac {x^3}{3}-\frac {7x^3}{3}+ {5x^2}]^2_0 -[\frac {x^3}{3}-\frac {7x^3}{3}+ {5x^2}]^2_0]^5_2 =[\frac {2^3}{3}-\frac {7*2^3}{3}+ {5*2^2}]-0-[\frac {5^3}{3}-\frac {7*5^3}{3}+ {5*5^2}]+[\frac {2^3}{3}-\frac {7*2^3}{3}+ {5*2^2}]](https://studentforums.biz/cgi-bin/mimetex.cgi?[\frac {x^3}{3}-\frac {7x^3}{3}+ {5x^2}]^2_0 -[\frac {x^3}{3}-\frac {7x^3}{3}+ {5x^2}]^2_0]^5_2 =[\frac {2^3}{3}-\frac {7*2^3}{3}+ {5*2^2}]-0-[\frac {5^3}{3}-\frac {7*5^3}{3}+ {5*5^2}]+[\frac {2^3}{3}-\frac {7*2^3}{3}+ {5*2^2}])
