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maths C2 doubt

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halosh92:
The points R(-2,5) S(2,1) T(-6,1) lie on the circumference of a circle. Find the equation of
RS and RT and hence find the coordinate of the centre of the circle
?????

astarmathsandphysics:
Method shown here

https://studentforums.biz/index.php/topic,5560.0.html

halosh92:

--- Quote from: astarmathsandphysics on February 19, 2010, 12:03:22 pm ---Method shown here

https://studentforums.biz/index.php/topic,5560.0.html

--- End quote ---

there is the method of the perpendicular bisector method could you explain it perpendicular bisector wise?

astarmathsandphysics:
Sorry saw three points and thought simultaneous eqs. When I get home

astarmathsandphysics:
R(-2,5) S(2,1) T(-6,1)
RS gradient =(1-5)/(2--2)=-1
Y=-X+C
5==--2+c c=3
Y=-X+3
RT gradient =(1-5)/(-6--2)=1
y=x+c
5=-2+c c=7
y=x+7

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