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astarmathsandphysics:
33)4v
for the top route the 12v is divided in ratio 1@ ie 4v:8v so midpoint is at 4v
but for the bottom bridge it is 2:1 ie 8v:4v so midpoint is 8v
difference between midpoints is 4v

astarmathsandphysics:
34)the voltage accros the resistor is 12* 3/(3+1)=9v
p=V^2/R=9^2 /3=27

Phosu:
nov 08
paper 1 ques 11, 21, 31

astarmathsandphysics:
11. Resloving for 2kg mass 2g-T=2a
resolving for 8kg mass T-6=8a
add these two 2g-6=10a so a=(2g-6)/10=1.4 c
21)c think of resistors in paralell and series. Maximise the resistance or extrension.
31)R=pl/A so halving the diameter means the resistance =pi*l/(d^2/4) is 4 times bigger and the current is divided by 4. d

Phosu:
plz explain how to solve
Nov 09  paper 1, ques 8 and 12,

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