New servers, hooraaaay! More bandwidth, more power.
Distance frim S_2 to M is sqrt(1^2 +0,8^)=1.28mso path difference =0.28mwhen f=1kHz wavelength=v/f=330/1000=0.33When f=4kHz wavelength=330/4000=0.0825minumum whenw/2=28 or 3w/2 =28 or 5w/2=28 or 7w/2 =28w=56 or w=18.7 or w=11.2 or w=8only two of these are between 8.25 and 33so only two minima