Qualification > Math
Vectors
Light:
1)the line T has vector equation r=2i+s(i+3j+4k)
find the position vectorS of the points on T which are exactly square root of 250 units from origin.
determine the position vector of point on T which is closest to point with position vector 6i-j+3k.
2)the centre line of an underground railway tunnel follows a line given by R=x(10,8,-1)for 0 or equal<t< or equal 40 the units being metres.the centre line of another tunnel at present stops at point wit position vector (200,100,-25) and it is proposed to extend this in a direction (5,7,Z).the constant Z has to be chosen so that at the point where one tunnel passes over the other,there is at least 15 metres difference in depth between centre lines of two tunnels.what restrictions does this impose on value Z?another requirement is that the tunnel must not be inclined at more than 5 degree to horizontal.What values of z satisfy both?
astarmathsandphysics:
When I get home
astarmathsandphysics:
1)the line T has vector equation r=2i+s(i+3j+4k)
find the position vectorS of the points on T which are exactly square root of 250 units from origin.
determine the position vector of point on T which is closest to point with position vector 6i-j+3k.
250=(2+s)^2+(3s)^2+(4s)^2
250=4+4s+s^2+9s^2+16s^2=4+4s+25s^2
25s^2+4s--246=0
s=-3.218 or 3.058
r=2i+(-3.218 or 3.058)(i+3j+4k)
d^2=|(2i+s(i+3j+4k)-(6i-j+3k.)|^2=(-4+s)^2+(3s+1)^2+(4s-3)^2
=16-8s+s^2+9s^2+6s+1+16s^2-24s+9=26s^2-26s+26
differentiate 52s-26=0 so s=1/2
then d^2=26*1/2^2-26*1/2+26=19.5 so d=sqrt(19.5)
astarmathsandphysics:
R=x(10,8,-1)
explain this?
Light:
the ans for ques 1 is 5i+9j+12k.and -1/13(15i+123j+164k).no so many decimal.
d^2=|(2i+s(i+3j+4k)-(6i-j+3k.)|^2=(-4+s)^2+(3s+1)^2+(4s-3)^2
=16-8s+s^2+9s^2+6s+1+16s^2-24s+9=26s^2-26s+26
differentiate 52s-26=0 so s=1/2
then d^2=26*1/2^2-26*1/2+26=19.5 so d=sqrt(19.5)
i dont get this part.mind explaning.the position vector(ans) is 5/2 i +3/2 j+2k.whats the working?
sorry for the R=x(10,8,-1).cant type the vector in matrix form.its actually line r= X(10i,8j,-1k) where X is the parameter.
thanx for solving.
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