Author Topic: Integration help pleaseeee!!!!  (Read 686 times)

Offline XFlufferzX

  • Newbie
  • *
  • Posts: 36
  • Reputation: 64
  • Gender: Female
Integration help pleaseeee!!!!
« on: January 17, 2010, 11:02:30 am »
Da paper is attached
I stucked in question 3 b ii)

b ii)

= [ 2 ln 5 - 3 ln 3 + ln5] - [ 2n ln - 3l + ln3]

= " 3 ln 5 - 4 ln 3 " <---- I didnt know how to get this by subtracting [ 2 ln 5 - 3 ln 3 + ln5] from [ 2n ln - 3l + ln3]

can someone explain it fer meh!

thankss alot ;D
Success is a journey, not a destination.

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Integration help pleaseeee!!!!
« Reply #1 on: January 17, 2010, 12:25:28 pm »
[ 2 ln 5 - 3 ln 3 + ln5] - [ 2 ln1 - 3ln1 + ln3]
=[3ln5-3ln3]-[0-0+ln3] since ln1=0
=3ln5-3ln3-ln3=3ln5-4ln3=ln(5^3/3^4)=ln(125/81}

Offline XFlufferzX

  • Newbie
  • *
  • Posts: 36
  • Reputation: 64
  • Gender: Female
Re: Integration help pleaseeee!!!!
« Reply #2 on: January 17, 2010, 12:56:45 pm »
Quote
[ 2 ln 5 - 3 ln 3 + ln5] - [ 2 ln1 - 3ln1 + ln3]
=[3ln5-3ln3]-[0-0+ln3] since ln1=0
=3ln5-3ln3-ln3=3ln5-4ln3=ln(5^3/3^4)=ln(125/81}

Thankss!!  :D
Success is a journey, not a destination.