need help in M1

[immortal]

den is da tention 320N
1200-600=1000a
a=0.6

1200-400-T=800a
T=1200-(400+800*0.6)
T=320N

[M-H]

peeps my query's y is the tension not considered in the calculation of F???

[halosh92]

peeps my query's y is the tension not considered in the calculation of F???

maybeee becuase the tow bar becomes slack....as the car is decelerating so the towbar beocmes loose ..imagine it in real life
im not sure though and i still dont understand how they arrived at their answer :SSS

[M-H]

maybeee becuase the tow bar becomes slack....as the car is decelerating so the towbar beocmes loose ..imagine it in real life
im not sure though and i still dont understand how they arrived at their answer :SSS

oh yh hw cud i 4gt that...ur ryt..i think the same..it mus b cz of that.....hey then arivin at the ans is n easy part! go thru it again im prety sure ul understand

[Ghost Of Highbury]

If anyone has the CIE A level mechanics book, plz refer to Page number 189, question 6 ii) I just need help with finding the tension in the towbar. im getting 210N, it's actually 550N or something.

[astarmathsandphysics]

Dont have it. Post the question.

[Ghost Of Highbury]

A car of mass 1200 kg traveling along a horizontal road experiences a resistance to motion of magnitude 140N. The car is accelerating at 0.5 m/s^2.
A trailer of 800 kg is now attached to the car. when the car and trailer are traveling along the same road the resistance to motion on the trailer has magnitude 500N. the resistance on the car and the forward driving force are the same as before the trailer was attached. find the force in the towbar between the car and the trailer.

[astarmathsandphysics]

F=ma for car initially
F-140=1200*0.5 so F=740
Now f=ma for car and trailer
740-140-T=1200a so 600-T=1200a
T-500=800a
Add these to get 100=2000a so a=100/2000=0.05
From the second equation T=500+800*0.05=540N

[Ghost Of Highbury]

Ah, got it, thanks. I drew the diagram incorrectly