Qualification > Math

Transformation Martices - IGCSE

<< < (2/5) > >>

the_grim_reaper:
Just one question. Does anyone know why the transformation of U to X in Nov 2009 Paper 4 IGCSE has a shear factor of -1???

Ghost Of Highbury:
 its always wiser to use the matrix method

take two object and correspoding image co-ordinates..

(-4,1) --> (-4,5)

(-1,1) --> (-1,2)

check the image attached

a shear transformation matrix with y-axis is invariant is = (1  0)
                                                                            (k   1)

here k = -1

AshWINNER:
i just have a doubt in determining the invariant line

So if i am correct, if a shear leaves a line x=a invariant, so invariant line is y axis rite?

And in stretch, the axis parallel to the two points which do not change is the invariant line right

Please illustrate ne probs in my concepts

And 1 more doubt

Shear factor=Distance moved due to shear/Perp dist from inv line

If distance/displacement due to shear is towards negative ,then will the shear factor be negative
If that is true, then that explains the shear factor of -1 in nov 2009 paper

Arthur Bon Zavi:

--- Quote from: AshWINNER on September 05, 2010, 08:32:49 am ---i just have a doubt in determining the invariant line

So if i am correct, if a shear leaves a line x=a invariant, so invariant line is y axis rite?

And in stretch, the axis parallel to the two points which do not change is the invariant line right

Please illustrate ne probs in my concepts

And 1 more doubt

Shear factor=Distance moved due to shear/Perp dist from inv line

If distance/displacement due to shear is towards negative ,then will the shear factor be negative
If that is true, then that explains the shear factor of -1 in nov 2009 paper

--- End quote ---

nov 2009 which paper 1 , 2 , 4??

cooldude:

--- Quote from: theonlyone on September 05, 2010, 09:08:48 am ---nov 2009 which paper 1 , 2 , 4??

--- End quote ---

42

Navigation

[0] Message Index

[#] Next page

[*] Previous page