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holtadit:
How would you find the inverse of  

 f(x) = 10^x

3y+2/y-1 = z   Make Y the subject of the formula

x+a = 2x-5/a  Make X the subject of the formula

PLEASE SHOW ALL WORKINGS !!

astarmathsandphysics:

--- Quote from: Ari Ben Canaan on January 02, 2010, 11:43:34 am ---How would you find the inverse of   

 f(x) = 10^x

3y+2/y-1 = z   Make Y the subject of the formula

x+a = 2x-5/a  Make X the subject of the formula

PLEASE SHOW ALL WORKINGS !!

y=10^x so x=log10y

Can you confirm the second question

x-2x=a-5/a
-x=a-5/a
x=5/a-1




--- End quote ---

holtadit:
f(x) = 10^x

Write down the value of f^?1(1)

Using your methid for the inverse of the above function... I dont get the correct answer (the right answer is 0)

Never mind the second question

Heres another one:
simplify (x^27/27)^1.5

nid404:
for f(x)=10^x

y=10^x
x=log y to the base 10
log of 1 =0
(but i doubt u are aware of logarithm)
so f'(1) implies f(x)=1

in that case 10^x=1
therefore x=0

nid404:
Can u check the ms for the simplification so i check if mine's right and then post the steps

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