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astarmathsandphysics:
When i get up

astarmathsandphysics:
Use s=ut+1/2at^2 twice

For the first two carriages
40=2u+2a
For the first for carraiges
80=4.4u+9.68a
Solve thes to get u=710/33
a=-50/33
then train takes s=(v^2-u^2)/2a=(710/33)^2/(2*50/33)=148.9
8 carrariages

Sue T:
thank you so much
 i'll study from the website u gave then if u can upload the questions it'll be great cuz i do need some practice :D

girl_92:

--- Quote from: astarmathsandphysics on December 14, 2009, 10:28:49 am ---Use s=ut+1/2at^2 twice

For the first two carriages
40=2u+2a
For the first for carraiges
80=4.4u+9.68a
Solve thes to get u=710/33
a=-50/33
then train takes s=(v^2-u^2)/2a=(710/33)^2/(2*50/33)=148.9
8 carrariages

--- End quote ---
Thanks  alot sir

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