hey but dont u need to consider the seperate side groups on the double bonded ca
C = C
on the left carbon above there is a methyl group on top and a hydrogen on bottom. Highest priority = methyl
on the right carbon above there is a chlorine on top and a methyl group on bottom. Highest priority = chlorine
Because the two highest priority groups on each carbon are on the same side, that is, on top, on their respective carbons, the molecule surely should be a Z isomer?
I know the base name will be
2-chlorobut-2-ene