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AS Chemistry Help Please

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vanibharutham:
Can some one please name the following compound,

the mark scheme says the answer is C and i dont think it is

i worked it out as this:

Take the highest priority groups on each carbon atom, which would be chlorine and methyl groups respectively

and because they are the same side it is a Z compound
hence i think that it is

(Z) 2-chlorobut-2-ene

MaNi_DaDuDe:
Answer is C.

The 1st carbon is in CH3 on the bottom right.

vanibharutham:
hey but dont u need to consider the seperate side groups on the double bonded ca


C = C

on the left carbon above there is a methyl group on top and a hydrogen on bottom. Highest priority = methyl
on the right carbon above there is a chlorine on top and a methyl group on bottom. Highest priority = chlorine

Because the two highest priority groups on each carbon are on the same side, that is, on top, on their respective carbons, the molecule surely should be a Z isomer?

I know the base name will be

2-chlorobut-2-ene

MaNi_DaDuDe:
I do not understand what you mean.. I used the method taught to me in my IGCSEs.

What board you doing?

I did CIE AS last year. .

vanibharutham:
Edexcel's New Specification (2008 onwards)

and what i was primarily asking was whether the compound an E isomer or a Z isomer?

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