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COPLANAR VECTORS!!!!!!!!!!!!HELP PLZZZZZZZZhey

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halosh92:
hello!
could anyone please explain to me what coplanar vectors are and how to find  the resultant and how to find the direction of the resultant .i have an exam in a week i need to know what exactly it is!!!!!rili appreciate your help
thx!
 ??? ???

staceyboy3:
If they are coplanar then all three lie in the same plane. That means 2D

The resultant force is the sum of the component forces of vectors. So if you have a vector of magnitude 8 going left and another vector of 6 going right, the resultant will be 2 (8 - 6). Its -6 because it is going in the opposite direction.

Now with vectors at an angle you have to first find the vertical and horizontal components. You'll have pythagora's theorem. sin=o/h , cos=a/h , tan=o/a. Easy way to remember is SOH CAH TOA.

Once you have the vertical and horizontal components, add them together and use pythagoras theorem again to find the magnitude.

To find the direction, you can use TOA. You need have the vertical and horizontal components. tan@ = o/a
changes to @ = tan-1(o/a) , which is inverse tan with -1 at the top right of tan (you can find it on your calculator.

If you didn't understand it please say. And remember, google is your friend ;)

This site will help if you go through it http://s-cool.co.uk/alevel/maths/vectors-lines-and-planes.html

halosh92:

--- Quote from: staceyboy3 on November 29, 2009, 11:16:06 pm ---If they are coplanar then all three lie in the same plane. That means 2D

The resultant force is the sum of the component forces of vectors. So if you have a vector of magnitude 8 going left and another vector of 6 going right, the resultant will be 2 (8 - 6). Its -6 because it is going in the opposite direction.

Now with vectors at an angle you have to first find the vertical and horizontal components. You'll have pythagora's theorem. sin=o/h , cos=a/h , tan=o/a. Easy way to remember is SOH CAH TOA.

Once you have the vertical and horizontal components, add them together and use pythagoras theorem again to find the magnitude.

To find the direction, you can use TOA. You need have the vertical and horizontal components. tan@ = o/a
changes to @ = tan-1(o/a) , which is inverse tan with -1 at the top right of tan (you can find it on your calculator.

If you didn't understand it please say. And remember, google is your friend ;)

This site will help if you go through it http://s-cool.co.uk/alevel/maths/vectors-lines-and-planes.html



--- End quote ---

thankyou so muchhhhhhhhhhhhhhhhhhhhhhhhhh!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! u were of great great help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! :) ;)

staceyboy3:
My pleasure :)

You doing your A-levels? Which ones?

halosh92:

--- Quote from: staceyboy3 on November 30, 2009, 11:26:11 am ---My pleasure :)

You doing your A-levels? Which ones?

--- End quote ---

am doing AS physics , maths and ICT only *CIE*
which ones are you doing??

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