Author Topic: ANY HELP! 2!  (Read 4051 times)

Offline Saladin

  • The Samurai
  • Honorary Member
  • SF V.I.P
  • *****
  • Posts: 6530
  • Reputation: 59719
  • Gender: Male
  • I believe in those who believe in me
    • Student Tech
Re: ANY HELP! 2!
« Reply #15 on: December 30, 2009, 07:55:04 am »
PPL THE DUDE IS BAQ

POST ANY DOUBTS AND ME OR NID WILL HELP U ANSA DEM! ;D

Offline mousa

  • SF Citizen
  • ***
  • Posts: 233
  • Reputation: 447
Re: ANY HELP! 2!
« Reply #16 on: December 30, 2009, 08:17:17 am »
can you plz explain this and as to why they are correct??

The conversion of graphite into diamond is an endothermic reaction (?H = +3 kJ mol–1).
C(graphite) ? C(diamond)
Which statements are correct?
1 The enthalpy change of atomisation of diamond is smaller than that of graphite.
2 The bond energy of the C–C bonds in graphite is greater than that in diamond.
3 The enthalpy change of combustion of diamond is greater than that of graphite

the markin scheme says that all of them are correct..

Offline mousa

  • SF Citizen
  • ***
  • Posts: 233
  • Reputation: 447
Re: ANY HELP! 2!
« Reply #17 on: December 30, 2009, 08:18:07 am »
and ya explain electropositivity... :)

Offline Saladin

  • The Samurai
  • Honorary Member
  • SF V.I.P
  • *****
  • Posts: 6530
  • Reputation: 59719
  • Gender: Male
  • I believe in those who believe in me
    • Student Tech
Re: ANY HELP! 2!
« Reply #18 on: December 30, 2009, 05:58:08 pm »
Electopositivity is the oppsosite of electronegativity. It is an element's ability to donate electrons electrons. Basically how easily something can donate electrons, and thus shows metallic character. For example, Cs is very electro-positive. It has the best ability to donate electrons. But Chlorine is not electropositive, it is electronegative and will want to pull electrons to itself.

Diamond and Graphite:

In order for this reaction to endothermic, 1 2 and 3 must be true.

2 must be true because the bonds broken (3 c-c) must have a greater bond energy than 4 c-c bonds in diamond, in order for more energy to required than given out, for the reaction to be endothermic. Becasue 3 C-C bonds are broken and 4 C-C bonds are made.

1 therefore must be true because atomisation means turning it into gaseous form, thus breaking 3C-C bonds, thus 1 is the same as 2.

3: An endothermic reaction means the material formed is less stable than its products. Thus, the enthalpy change of burning diamond should be greater than graphite, as diamond is less stable and will lose more energy than graphite.

Hope this asnwers ur q. This is by far one of the hardest qs i have answered.

Offline Saladin

  • The Samurai
  • Honorary Member
  • SF V.I.P
  • *****
  • Posts: 6530
  • Reputation: 59719
  • Gender: Male
  • I believe in those who believe in me
    • Student Tech
Re: ANY HELP! 2!
« Reply #19 on: January 11, 2010, 04:44:07 pm »
Please post probs!

Offline mousa

  • SF Citizen
  • ***
  • Posts: 233
  • Reputation: 447
Re: ANY HELP! 2!
« Reply #20 on: January 11, 2010, 05:10:31 pm »
Please post probs!
lol, you recovered from the Question which i have posted( diamond and graphite) here is another one  :P

The density of ice is 1.00 g cm–3.
What is the volume of steam produced when 1.00 cm3 of ice is heated to 323 °C (596 K) at a
pressure of one atmosphere (101 kPa)?

[1 mol of a gas occupies 24.0 dm3 at 25 °C (298 K) and one atmosphere.]
A 0.267 dm3  B 1.33 dm3  C 2.67 dm3  D 48.0 dm


Offline Saladin

  • The Samurai
  • Honorary Member
  • SF V.I.P
  • *****
  • Posts: 6530
  • Reputation: 59719
  • Gender: Male
  • I believe in those who believe in me
    • Student Tech
Re: ANY HELP! 2!
« Reply #21 on: January 11, 2010, 05:19:15 pm »
Srry I do Edexcel, dont have gas Laws.

Offline mousa

  • SF Citizen
  • ***
  • Posts: 233
  • Reputation: 447
Re: ANY HELP! 2!
« Reply #22 on: January 11, 2010, 05:24:55 pm »
Srry I do Edexcel, dont have gas Laws.

np dude  :)

Offline Sweet_03

  • SF Immigrant
  • **
  • Posts: 55
  • Reputation: 39
Re: ANY HELP! 2!
« Reply #23 on: January 11, 2010, 08:48:46 pm »
yur so helpful : )

i hav one Q - in Chemistry !
wats electronegativity :s ?

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: ANY HELP! 2!
« Reply #24 on: January 11, 2010, 08:59:57 pm »
Basically the ability of atoms to attrat electrons. Every atoms has a number, deonting it's electronegativity - it's ability to attract electrons. The most electronegative is fluorine, I think  -2. My subject is bot chemistry.

Offline Sweet_03

  • SF Immigrant
  • **
  • Posts: 55
  • Reputation: 39
Re: ANY HELP! 2!
« Reply #25 on: January 11, 2010, 09:08:58 pm »
aha! nd how do i know the number ?
By the way , yur right ! its is fluorine but i nvr knew why ?
ok thank you astar : ) that made it clearer

Offline mousa

  • SF Citizen
  • ***
  • Posts: 233
  • Reputation: 447
Re: ANY HELP! 2!
« Reply #26 on: January 12, 2010, 02:59:46 am »

The density of ice is 1.00 g cm–3.
What is the volume of steam produced when 1.00 cm3 of ice is heated to 323 °C (596 K) at a
pressure of one atmosphere (101 kPa)?

[1 mol of a gas occupies 24.0 dm3 at 25 °C (298 K) and one atmosphere.]
A 0.267 dm3  B 1.33 dm3  C 2.67 dm3  D 48.0 dm


[/quote]

anyone else???

Offline Sweet_03

  • SF Immigrant
  • **
  • Posts: 55
  • Reputation: 39
Re: ANY HELP! 2!
« Reply #27 on: January 12, 2010, 06:29:42 am »
the dude ,
since yur doing Physics Edexcel !i jst wana ask yu , is momentum in the new syllabus ?

Offline Saladin

  • The Samurai
  • Honorary Member
  • SF V.I.P
  • *****
  • Posts: 6530
  • Reputation: 59719
  • Gender: Male
  • I believe in those who believe in me
    • Student Tech
Re: ANY HELP! 2!
« Reply #28 on: January 12, 2010, 07:35:05 am »
NO!

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: ANY HELP! 2!
« Reply #29 on: January 12, 2010, 09:35:06 am »
The density of ice is 1.00 g cm–3.
What is the volume of steam produced when 1.00 cm3 of ice is heated to 323 °C (596 K) at a
pressure of one atmosphere (101 kPa)?

[1 mol of a gas occupies 24.0 dm3 at 25 °C (298 K) and one atmosphere.]
A 0.267 dm3  B 1.33 dm3  C 2.67 dm3  D 48.0 dm

ig of gas =1/18mol sin 1 mol water weighs 18g
so 1g gas occupies 24/18dm3
V1/T1=V2/T2 so V2=V1*T2/T1=24/18*(323+273)/(25+273)=2.585dm3

For some reason I put 1/18 instead 24/18
« Last Edit: January 12, 2010, 02:24:18 pm by astarmathsandphysics »