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Author Topic: CIE physics paper 2  (Read 11774 times)

Offline Tyserius

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Re: CIE physics paper 2
« Reply #75 on: November 16, 2009, 12:33:23 pm »
Quote from: aragornluv37 on November 16, 2009, 12:17:31 pm
WHAT?! How could you get 33 for the angle?  ???
I got the 7.4 m/s, but when I calculated with sin (Theta) = 4/6.2, I got 40 degree for the angle.
Don't tell me I got the sin formula wrong...

OH MY GOD!!!! i JUST REALIZED IT'S WRONG!!!!! SHOULD'VE BEEN TAN THETA!!!!!!!
I AM SO DEPRESSED RIGHT NOW!! I'VE ALREADY LOST SO MANY MARKS BY NOT HAVING THE TIME TO DO SOME QUESTIONS!

Sorry for the Caps, I would like to ask forgiveness from all of you.

Nah, it's alright about the caps :) What's done is done! Don't regret on the past. Study more when A2 begins then! :)

@Tumble Bug : OMG! The resistance table was the easiest and fastest to score...
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Offline Tumble Bug

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Re: CIE physics paper 2
« Reply #76 on: November 16, 2009, 12:42:59 pm »
Quote from: Tyserius on November 16, 2009, 12:33:23 pm

@Tumble Bug : OMG! The resistance table was the easiest and fastest to score...

that makes me feel ALOT better!!!

i didnt have time...the woman was like 5 mins and i still had 3 questions to go!! :( :'(
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Offline Tyserius

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Re: CIE physics paper 2
« Reply #77 on: November 16, 2009, 12:45:48 pm »
Quote from: Tumble Bug on November 16, 2009, 12:42:59 pm
that makes me feel ALOT better!!!

i didnt have time...the woman was like 5 mins and i still had 3 questions to go!! :( :'(

You should have skipped the questions that were taking more time first... But oh well, what's done is done! No use thinking back! Look on the bright side, another paper is done! :D
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Offline Tumble Bug

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Re: CIE physics paper 2
« Reply #78 on: November 16, 2009, 12:48:41 pm »
Quote from: Tyserius on November 16, 2009, 12:45:48 pm
You should have skipped the questions that were taking more time first... But oh well, what's done is done! No use thinking back! Look on the bright side, another paper is done! :D

yea..InshALLAH all will go well..
2day was my last!! :) *dances*
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Offline Tyserius

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Re: CIE physics paper 2
« Reply #79 on: November 16, 2009, 12:49:40 pm »
Quote from: Tumble Bug on November 16, 2009, 12:48:41 pm
yea..InshALLAH all will go well..
2day was my last!! :) *dances*

Hahaha! Same here! I already had my celebration :P
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Q80BOY

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Re: CIE physics paper 2
« Reply #80 on: November 16, 2009, 12:51:28 pm »
i think its too late to remind u guys that exam discussion only takes place 24 hours AFTER the exam!!

u finished discussing the paper and are about to leave now :P

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Offline Tumble Bug

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Re: CIE physics paper 2
« Reply #81 on: November 16, 2009, 12:53:34 pm »
Quote from: Q80BOY on November 16, 2009, 12:51:28 pm
i think its too late to remind u guys that exam discussion only takes place 24 hours AFTER the exam!!

u finished discussing the paper and are about to leave now :P



loooooooollllllllll


my bad!! :P ;D
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Offline Tyserius

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Re: CIE physics paper 2
« Reply #82 on: November 16, 2009, 12:54:20 pm »
Quote from: Q80BOY on November 16, 2009, 12:51:28 pm
i think its too late to remind u guys that exam discussion only takes place 24 hours AFTER the exam!!

u finished discussing the paper and are about to leave now :P



Well.. It was already started lol. So, I thought it is already allowed for discussion? >_<
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Offline ilmarien

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Re: CIE physics paper 2
« Reply #83 on: November 16, 2009, 01:01:35 pm »
 :o
Whoops, sorry. I also thought that it's already okay to discuss it.
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Q80BOY

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Re: CIE physics paper 2
« Reply #84 on: November 16, 2009, 01:08:49 pm »
now u know for next time ;) :D
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Offline falafail

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Re: CIE physics paper 2
« Reply #85 on: November 16, 2009, 01:32:14 pm »
Quote from: Tyserius on November 16, 2009, 11:54:12 am
The velocity question was actually to just use your ruler to draw the lines D: And you can actually double check by using the following formula :

Let vR be the resultant velocity, vx be the horizontal velocity and vy be the vertical velocity.

vR = Square root of (vx2 + vy2)

Then the horizontal angle can be found by tan \theta = vy/vx

The vertical angle then can be obtained by 90 - \theta

nono, not the vector diagram thing. the one before, the second part. i tried using the v2 = u2 blahblahblah formula but i didn't get it right :(


oh well.
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Offline Tyserius

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Re: CIE physics paper 2
« Reply #86 on: November 16, 2009, 02:27:57 pm »
It's because the vertical component begins with 0. So v = \sqrt(2gh)
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Offline falafail

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Re: CIE physics paper 2
« Reply #87 on: November 16, 2009, 02:37:59 pm »
Quote from: Tyserius on November 16, 2009, 02:27:57 pm
It's because the vertical component begins with 0. So v = \sqrt(2gh)

yessss i knowwwww i'm saying i couldn't get the answer right (6.22 or whatever it was)
i left that though so i'll prolly get marks for it.
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Offline MaNi_DaDuDe

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Re: CIE physics paper 2
« Reply #88 on: November 16, 2009, 05:47:22 pm »
the paper had finished in every country before discussion started. :)

I made sure.
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Offline vince_24

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Re: CIE physics paper 2
« Reply #89 on: November 16, 2009, 07:27:55 pm »
The phase difference I got was 270 degrees. Also, What did you guys get for the amplitude? There is a lot of mixed answers going around at our school. Only 1 mark though :D I wrote 3/4 A
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